In this program, you are to simulate a 2-pass assembler in C++. The input to thi

ID: 3823301 • Letter: I

Question

In this program, you are to simulate a 2-pass assembler in C++. The input to this program is an assembly language program and the output should include a symbol table and the machine code version of the input. You have to echo the input. Do file I/O.

You are implementing two classical algorithms (Fig. 6.1 & Fig 6.2).

INPUT

ORG $00000500

MOVE #79, $00002000

TRAP #1 ;READLN (Y), INPUT INTO DO

LOOP1 MOVE DO, $00020004 ;STORE DO IN LOCATION Y

MOVE $00002000, DO ;FETCH VARIABLE I FOR THE AD

ADD $00002004, DO ;ADD Y+1

MOVE DO, $00002002 ; STORE THE SUM IN X

LOOP2 ADDI #18, $00002002 ;ADD 18 TO X

TRAP #2 ; PRINT X

TRAP #0 ; STOP

END

OUTPUT

Address Machine code Operands Instructions

00000500 33FC 4F MOVE #79, $00002000

----- ----- -- -- -- --

Explanation / Answer

Answer:

Assembly Language Code :

.LC0:
        .string "Enter a positive integer: "
.LC1:
        .string "Sum = "
main:
        push    rbp
        mov     rbp, rsp
        sub     rsp, 16
        mov     DWORD PTR [rbp-4], 0
        mov     esi, OFFSET FLAT:.LC0
        mov     edi, OFFSET FLAT:std::cout
        call    std::basic_ostream<char, std::char_traits<char> >& std::operator<< <std::char_traits<char> >(std::basic_ostream<char, std::char_traits<char> >&, char const*)
        lea     rax, [rbp-12]
        mov     rsi, rax
        mov     edi, OFFSET FLAT:std::cin
        call    std::basic_istream<char, std::char_traits<char> >::operator>>(int&)
        mov     DWORD PTR [rbp-8], 1
.L3:
        mov     eax, DWORD PTR [rbp-12]
        cmp     DWORD PTR [rbp-8], eax
        jg      .L2
        mov     eax, DWORD PTR [rbp-8]
        add     DWORD PTR [rbp-4], eax
        add     DWORD PTR [rbp-8], 1
        jmp     .L3
.L2:
        mov     esi, OFFSET FLAT:.LC1
        mov     edi, OFFSET FLAT:std::cout
        call    std::basic_ostream<char, std::char_traits<char> >& std::operator<< <std::char_traits<char> >(std::basic_ostream<char, std::char_traits<char> >&, char const*)
        mov     rdx, rax
        mov     eax, DWORD PTR [rbp-4]
        mov     esi, eax
        mov     rdi, rdx
        call    std::basic_ostream<char, std::char_traits<char> >::operator<<(int)
        mov     eax, 0
        leave
        ret
__static_initialization_and_destruction_0(int, int):
        push    rbp
        mov     rbp, rsp
        sub     rsp, 16
        mov     DWORD PTR [rbp-4], edi
        mov     DWORD PTR [rbp-8], esi
        cmp     DWORD PTR [rbp-4], 1
        jne     .L7
        cmp     DWORD PTR [rbp-8], 65535
        jne     .L7
        mov     edi, OFFSET FLAT:std::__ioinit
        call    std::ios_base::Init::Init()
        mov     edx, OFFSET FLAT:__dso_handle
        mov     esi, OFFSET FLAT:std::__ioinit
        mov     edi, OFFSET FLAT:std::ios_base::Init::~Init()
        call    __cxa_atexit
.L7:
        nop
        leave
        ret
_GLOBAL__sub_I_main:
        push    rbp
        mov     rbp, rsp
        mov     esi, 65535
        mov     edi, 1
        call    __static_initialization_and_destruction_0(int, int)
        pop     rbp
        ret

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