A c++ program that prompts the user to enter a name or ID number then the progra

Question

A c++ program that prompts the user to enter a name or ID number then the program uses the input to scan and search for a Students ID # or name from a pre-created file that contains the students information(the name, student ID number, grade level, residence address, city, state, zip-code, and home phone number) in a horizontal column format using at least one function and a loop. Once the program finds the information on the student, all the information pertaining to said student( in the same row, separated by commas) should be displayed to the screen. Please do not use the header file (Assuming the file has structure in format: last name first name student ID number grade level residence address city state zip-code phone number)

i.e.

Explanation / Answer

/* This is used for importing header files */
#include <iostream>
#include <string>

using namespace std;

/*Define the structure */
struct student {
string id;
string lname;
string fname;
int grade;
string address;
string city;
string state;
int zip;
long long phone;
};

/*funtion to display data*/
void showData(struct student s)
{
cout<<" ID: "<<s.id<<" LAST NAME: "<<s.lname
<<" FIRST NAME: "<<s.fname<<" GRADE: "<<s.grade
<<" ADDRESS: "<<s.address<<" CITY: "<<s.city
<<" STATE: "<<s.state<<" ZIPCODE: "<<s.zip<<" PHONE: "<<s.phone;
}

/*Funtion to get data from user*/
struct student setData()
{
struct student s1;
cout<<"Enter Student Id ";
cin>>s1.id;
cout<<"Enter Last Name ";
cin>>s1.lname;
cout<<"Enter First Name ";
cin>>s1.fname;
cout<<"Enter Student Grade ";
cin>>s1.grade;
cout<<"Enter Residential Address ";
cin.ignore(); /*user to clear buffer, so that text including space can be read easily*/
getline(cin,s1.address);
cout<<"Enter City Name ";
cin>>s1.city;
cout<<"Enter State Name ";
cin>>s1.state;
cout<<"Enter Zip Code ";
cin>>s1.zip;
cout<<"Enter Phone No. ";
cin>>s1.phone;
  
  
return s1;
}

/*Funtion which will execute first*/
int main() {
   // your code goes here
struct student s1;
s1 = setData();
string search;
cout<<"Enter ID or First Name or Last Name to search";
cin>>search;
if(s1.id == search || s1.lname == search || s1.fname == search)
showData(s1);
else
cout<<"No DATA FOUND";
  
   return 0;
}

/*
Above example is for reading one input, searching that input and if found display it.
To search from many records, use loop as following
struct student s1[10];
for(int i=0;i<10;i++)
s1[i]= setData();
cout<<"Enter ID or First Name or Last Name to search";
cin>>search;
for(int i=0;i<10;i++)
{
if(s1[i].id == search || s1[i].lname == search || s1[i].fname == search)
showData(s1[i]);
}

In found any issue, please use comment section to let me know.

*/

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