Write a program that counts the number of negative values, the number of positiv

Question

Write a program that counts the number of negative values, the number of positive values and the number of zeros in a floating point array. Instead of performing these counts inside the main program, each count should be calculated by a USER-DEFINED FUNCTION.

Specificially, the program should:

• greet the user,

• prompt for and input the length of the array;

• idiotproof the array length;

• dynamically allocate the array;

• check that the allocation was successful;

• prompt for and input the values in the array

• count the number of negative values by calling a USER-DEFINED FUNCTION;

• count the number of positive values by calling a USER-DEFINED FUNCTION;

• count the number of zeros by calling a USER-DEFINED FUNCTION;

• output the numbers of negative, positive and zero values in the array;

• deallocate the array.

NOTE: You MUST calculate each of the three counts in ITS OWN user-defined function; you are ABSOLUTELY FORBIDDEN to calculate more than one of them in the same user-defined function.

Please provide answer in C

Explanation / Answer

#include<stdio.h>
#include<stdlib.h>
int find_positive(float[] ,int );
int find_negative(float[] ,int );
int find_zero(float[] ,int );
int main()
{
int i,size,no_pos,no_neg,no_zero;
float arr[100];
printf("Enter the size of the array ");
scanf("%d",&size);
printf("Enter the values into the array ");
for(i=0;i<size;i++)
{
scanf("%f",&arr[i]);
}
no_pos=find_positive(arr,size);
no_neg=find_negative(arr,size);
no_zero=find_zeros(arr,size);
printf(" The number of positive numbers in the list = %d ",no_pos);
printf(" The number of negative numbers in the list = %d ",no_neg);
printf(" The number of zeros in the list = %d ",no_zero);
return 0;
}
int find_positive(float arr[100],int size)
{
int i,count=0;
for(i=0;i<size;i++)
{
if(arr[i]>0)
{
count++;
}
}
return count;
}
int find_negative(float arr[100],int size)
{
int i,count=0;
for(i=0;i<size;i++)
{
if(arr[i]<0)
{
count++;
}
}
return count;
}
int find_zeros(float arr[100],int size)
{
int i,count=0;
for(i=0;i<size;i++)
{
if(arr[i]==0)
{
count++;
}
}
return count;
}

OUTPUT:-

Enter the size of the array
6
Enter the values into the array
2.2
6.5
0
-5.8
0.00
-22.11

The number of positive numbers in the list = 2

The number of negative numbers in the list = 2

The number of zeros in the list = 2

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