Write a method called filterRange that accepts an ArrayList of integers and two

Question

Write a method called filterRange that accepts an ArrayList of integers and two integer values min and max as parameters and removes all elements whose values are in the range min through max (inclusive). For example, if a variable called list stores the values [4, 7, 9, 2, 7, 7, 5, 3, 5, 1, 7, 8, 6, 7] the call of filterRange (list, 5, 7); should remove all values between 5 and 7, changing the to store [4, 9, 2, 3, 1, 8]. If no elements in range min-max are found in the list, or if the list is initially empty, the list's contents are unchanged

Explanation / Answer

ArrayListValuesTest.java

import java.util.ArrayList;

public class ArrayListValuesTest {

  
   public static void main(String[] args) {
   ArrayList<Integer> list = new ArrayList<Integer>();
   list.add(4);
   list.add(7);
   list.add(9);
   list.add(2);
   list.add(7);
   list.add(7);
   list.add(5);
   list.add(3);
   list.add(5);
   list.add(1);
   list.add(7);
   list.add(8);
   list.add(6);
   list.add(7);
   System.out.println(list);
   filterRange(list, 5, 7);
   System.out.println(list);
  
   }
   public static ArrayList<Integer> filterRange(ArrayList<Integer> list, int min, int max) {
       for(int i=0; i<list.size(); i++){
           if(list.get(i) >= min && list.get(i) <= max) {
               list.remove(i);
               i--;
           }
       }
       return list;
   }

}

Output:

[4, 7, 9, 2, 7, 7, 5, 3, 5, 1, 7, 8, 6, 7]
[4, 9, 2, 3, 1, 8]

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