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Your solution will be compared to a master solution. Each correct value in a cel

ID: 3825673 • Letter: Y

Question

Your solution will be compared to a master solution. Each correct value in a cell earns one point. There are no partial credits. There are 20 cells in the table that need to be filled Assume that you have been assigned 192.168.111.129/28. How many bits are borrowed to create the subnet field? (1 Point for the correct answer) What is the maximum number of subnets that can be created with this number of bits? (1 Point for the correct answer) How many bits can be used to create the host space? (1 point for the correct answer) What is the maximum number of possible IP addresses in the host space? (1 Point for the correct answer) What is the maximum number of IP addresses that can be actually assigned to a host device in a subnet? (1 Point for the correct answer) What is the subnet mask in binary representation? (1 Point for the correct answer) What is the subnet mask in decimal representation? (1 Point for the correct answer)

Explanation / Answer

1) It is class C network address. First 24 bits are network and last 8 bits are used for hosts.

Given 28 bits used for mask.

So, 24 bits from network, so remaining 4 bits are borrowed from host for subnetting.

2) Maximum 16 subnets can be created with 4 bits of last octet.

3) Last octet has 8 bits. Already 4 bits are used for subnetting. Remaining last 4 bits of last octet used to create the host space.

4) The following address range is possible:

Addresses from 192.168.111.128 to 192.168.111.143

5) Subnet Mask in Binary: 11111111. 11111111. 11111111. 11110000

6) Subnet Mask in Decimal: 255.255.255.240