A company pays its salespeople on a commission basis. The salespeople each recei

Question

A company pays its salespeople on a commission basis. The salespeople each receive $200 per week plus 9 percent of their gross sales for that week. For example, a salesperson who grosses $5000 in sales in a week receives $200 plus 9 percent of$5000, or a total of $650. Write a program (using an array of counters) that determines how many of the salespeople earned salaries in each of the following ranges (assume that each salesperson's salary is truncated to an integer amount): a)$200-299 b)$300-399 c)$400-499 d) $500-599 e) $600-699 f) $700-799 g) $800-899 h) $900-999 i) $1000 and over.

Explanation / Answer

using namespace std;
#include <iostream>
#include <string>
int main()
{
//let us hardcode sales of 20 salesperson in an array
int sales[20]={25000,3500,45000,5500,6500,75000,8500,9500,10500,25000,3500,4500,5500,6500,7500,8500,9500,10500,1110,1000};
int salaries[20];
// we have 9 categories of salaries ,so create an array of 9 counters and intialize all values to zero
int count[9]={0,0,0,0,0,0,0,0,0};
for(int i=0;i<sizeof(sales)/sizeof(int);i++)
{
salaries[i]=200+((int)(0.09*sales[i]));
if(salaries[i]>=200&&salaries[i]<=299)
count[0]++;
else if(salaries[i]>=300&&salaries[i]<=399)
count[1]++;
else if(salaries[i]>=400&&salaries[i]<=499)
count[2]++;
else if(salaries[i]>=500&&salaries[i]<=599)
count[3]++;
else if(salaries[i]>=600&&salaries[i]<=699)
count[4]++;
else if(salaries[i]>=700&&salaries[i]<=799)
count[5]++;
else if(salaries[i]>=800&&salaries[i]<=899)
count[6]++;
else if(salaries[i]>=900&&salaries[i]<=999)
count[7]++;
else if(salaries[i]>=1000)
count[8]++;
}
for(int i=0;i<9;i++)
{
cout<<" Category "<<i+1<<" : "<<count[i];
}

return 0;
}

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