the script should be in c programming Create script that will use a Cramer\'s ru

Question

the script should be in c programming

Create script that will use a Cramer's rule to find the solution of At = b. The A a 3 main B a 3a t matrix. (For the of values of entries in matrices. you have to use POINTERS!) Then the value of x,y and z can be [a_1 a_2 a_3 b_1 b_2 b_3 c_1 c_2 c_3] [x V z] = [d_1 d_2 d_3] x = |d_1 d_2 d_3 b_1 b_2 b_3 c_1 c_2 c_3| / |a_1 a_2 a_3 b_1 b_2 b_3 c_1 c_2 c_3| v = |d_1 d_2 d_3 b_1 b_2 b_3 c_1 c_2 c_3| / |a_1 a_2 a_3 b_1 b_2 b_3 c_1 c_2 c_3| and z = |d_1 d_2 d_3 b_1 b_2 b_3 c_1 c_2 c_3| / |a_1 a_2 a_3 b_1 b_2 b_3 c_1 c_2 c_3| http.// wikipedia_org/ /Cramer%27 _rule indicates the determinant Check you result with [3 1 1 -2 1 1 1 2 0] [x y z] = [6 7 5] if you had hard time reading numbers... [3 1 1 -2 1 1 1 2 0] [x y z] = [6 7 5]

Explanation / Answer

#include int det3(int a[3][3]); int main(void) {     int A[3][3];     int B[3];     printf("This program uses Cramer's Rule to solve a linear system.             Enter each of 3 linear equations as four integers separated by space.               For example, x - 2y + 3z = 4 should be entered as 1 -2 3 4"); printf(" Enter equation 1: ");     scanf("%i %i %i %i", &A[0][0], &A[0][1], &A[0][2], &B[0]);     printf("Enter equation 2: ");     scanf("%i %i %i %i", &A[1][0], &A[1][1], &A[1][2], &B[1]);     printf("Enter equation 3: ");     scanf("%i %i %i %i", &A[2][0], &A[2][1], &A[2][2], &B[2]);     /*Finding determinants*/     int detx[3][3] = {{B[0],A[0][1],A[0][2]},{B[1],A[1][1],A[1][2]},                           {B[2],A[2][1],A[2][2]}};     int dety[3][3] = {{A[0][0],B[0],A[0][2]},{A[1][0],B[1],A[1][2]},                           {A[2][0],B[2],A[2][2]}};     int detz[3][3] = {{A[0][0],A[0][1],B[0]},{A[1][0],A[1][1],B[1]}                           {A[2][0],A[2][1],B[2]}};     /* Code that determines if the system has a unique solution */ if(det3(A)!=0) printf(" System has a unique solution ( %d,%d,%d)", det3(detx)/det3(A),det3(dety)/det3(A),det3(detz)/det3(A));       else              printf(" System does not have a unique solution because determinant is 0");     return 0; } int det3(int a[3][3]) {     return (a[0][0]*a[1][1]*a[2][2])-(a[0][0]*a[1][2]*a[2][1]),                 +(a[0][1]*a[1][2]*a[2][0])-(a[0][1]*a[1][0]*a[2][2]),                 +(a[0][2]*a[1][0]*a[2][1])-(a[0][2]*a[1][1]*a[2][0]); 2 }

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