C++ question How to compare two int if they are the same? I recieve this error:

Question

C++ question

How to compare two int if they are the same? I recieve this error:

In function 'int main()':
error: invalid types 'int[int]' for array subscript
if (target[i] == friends[n].idnum[i]) //compare Ints
^
error: invalid types 'int[int]' for array subscript
if (target[i] == friends[n].idnum[i]) //compare Ints

My code:

in.open(input.c_str());
   if (!in)
       cout << "Error opening file." << endl;
   else
   {  
       int target;
       int n2 = 0;
       in >> target;
       while (in)
       {
           in >> target;
           n2++; //How many targets
           for (int i = 0; i < n2; i++)
           {
               if (target[i] == friends[n].idnum[i])   //compare Ints
               {
                   outf << "ID#: " << friends[i].idnum << endl;
                   outf << "Name: " << friends[i].firstname + ',' + friends[i].lastname << endl;;
                   outf << "Test score: " << friends[i].score << endl;
                   outf << "Test responses: " << friends[i].answers << endl;
                   outf << endl;
               }
               else
               {
                   outf << target << "is not a valid student ID# " << endl;
               }
           }
       }
       in.close();
   }

Desired output:

ID#:     56
Name: Larry Black
Test score: 95
Test responses: abcdabcdabcdabcdabcbbbbbbbb

13 is not a valid student ID#

ID#:     10
Name: Matthew Adams
Test score: 15
Test responses: aaaaaaaaaaaa

ID#:     19
Name: Jennifer Schwartz
Test score: 75
Test responses: aabbcccdabcdabcdabcd

-5 is not a valid student ID#

Explanation / Answer

Variable target is declared as an integer variable.

In the statement: if(target[i] == friends[n].idnum[i]) , target is used as an array.

Structure array friends is accessed using index variable i. Feild idnum is accessed as friends[i].idnum

Change the above statement as follows:

if(target == friends[i].idnum)

This will resolve the issue.

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