1. I have a Class C subnet mask of 255.255.255.240 a. How many subnets on the ne

Question

1. I have a Class C subnet mask of 255.255.255.240

a. How many subnets on the network?

b. How many host per subnet?

c. What is the maximum number of unique host addresses on the network?

2. I have a network IP address of 192.168.73.67 with a subnet mask of 255.255.255.224 (Class C)

a. What is the network ID? Hint: use ANDing to find the network ID, you can use calculator in Windows to find binary values.

b. What is the Broadcast address? Hint: use the chart on page 406 to find what subnet range your IP falls into.

Explanation / Answer

Given c subnet mask is 255.255.255.240

Binary representation for given maks is: 11110000

In the given mask there are 4 subnet bits(1's) and 4 host bits(0's)

a) The bumber of subnets:

2x-2,where x no.of subnet bits.
=>24-2
=>16-2
=>14.
Therefore number of subnets are 14.

b) host per subnet:

2x-2,where x no.of host bits.
=>24-2
=>16-2
=>14.
Therefore number of hosts per one subnet 14.

2) Given Ip address is 192.168.73.67 and mask is 255.255.255.224

a) Network ID

192.168.73.67 - 11000000.10101000.01001001.01000011
255.255.255.224 - 11111111.11111111.11111111.11100000

By performing AND operation

Nwtwork ID - 11000000.10101000.01001001.01000000
- 192.168.73.64

c) Broadcast address:

Mask = 255.255.255.224

32 is the first subnet and 64 is the second subnet. The broadcast address is always the number before the next subnet. The broadcast address of the 32 subnet is 63 .The broadcast address for the 64 subnet is 95. The broadcast address for the 96 subnet is 127. The broadcast address for the 160 subnet is 191. The broadcast address for the 192 subnet is 223.

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.