Analyze the following code: import javafx.application.Application; import javafx

Question

Analyze the following code: import javafx.application.Application; import javafx.scene.Scene; import javafx.scene.control.Button; import javafx.stage.Stage; public class Test extends Application { @Override // Override the start method in the Application class public void start(Stage primaryStage) { // Create a button and place it in the scene Button btOK = new Button("OK"); btOK.setOnAction(e -> System.out.println("OK 1")); btOK.setOnAction(e -> System.out.println("OK 2")); Scene scene = new Scene(btOK, 200, 250); primaryStage.setTitle("MyJavaFX"); // Set the stage title primaryStage.setScene(scene); // Place the scene in the stage primaryStage.show(); // Display the stage } /** * The main method is only needed for the IDE with limited JavaFX * support. Not needed for running from the command line. */ public static void main(String[] args) { launch(args); } }

When clicking the button, the program displays OK1.

When clicking the button, the program displays OK2.

When clicking the button, the program displays OK1 OK2.

The program has a compile error, because the setOnAction method is invoked twice.

When clicking the button, the program displays OK1.

When clicking the button, the program displays OK2.

When clicking the button, the program displays OK1 OK2.

The program has a compile error, because the setOnAction method is invoked twice.

Explanation / Answer

When the button has been clicked, it responds with a value Ok2 on to the screen.

So, the answer is:

When clicking the button, the program displays OK2.

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