Please help me with this C++ assignment! RIGHTMOST CHAR CHALLENGE DESCRIPTION: Y

Question

Please help me with this C++ assignment!

RIGHTMOST CHAR

CHALLENGE DESCRIPTION:

You are given a string 'S' and a character 't'. Print out the position of the rightmost occurrence of 't' (case matters) in 'S' or -1 if there is none. The position to be printed out is zero based.

INPUT SAMPLE:

The first argument will be a path to a filename (e.g. the program was executed with >>> ./a.out input.txt <<<<< ), containing a string and a character, comma delimited, one per line. Ignore all empty lines in the input file. E.g.

OUTPUT SAMPLE:

Print out the zero based position of the character 't' in string 'S', one per line. Do NOT print out empty lines between your output.
E.g.

Explanation / Answer

PROGRAM CODE:

#include <iostream>
#include <sstream>
#include <fstream>
using namespace std;

int rightMostChar(string word, char ch)
{
   for(int i=word.length()-1; i>=0; i--)
   {
       if(word[i] == ch)
           return i;
   }
   return -1;
}
int main(int argc, char *argv[]) {
   string line = "";
// from the question it is understood that the file name will be provided as a command line argument. So this is where we instantiate the file stream
   ifstream in(argv[0]);
// This is where we read through each line of the file
   while(getline(in, line))
   {
       string word1, word2;
       char ch;
       stringstream ss(line);
// here we are reading each word of the file after splitting them with the delimitter as ','
       getline(ss, word1, ',');
       getline(ss, word2, ',');
       cout<<rightMostChar( word1, word2.at(0))<<endl;
   }
   return 0;
}

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