In c++ char x[10]; x[0] = \'a\'; x[1] = \'b\'; x[2] = \'c\'; x[3] = \'d\'; x[4]

Question

In c++

char x[10]; x[0] = 'a';

x[1] = 'b'; x[2] = 'c';

x[3] = 'd'; x[4] = 'e';

x[5] = 'f'; x[6] = 'g'; x[7] = 'h'; x[8] = 'i'; x[9] = 'j'; for (int i = 0; i<10; i++){ cout<< x[i]; // print each character cout << " "; }

cout << endl;

for (int i = 0; i<10; i++)

{ cout << (int)x[i]; // The actual data in x[0] is 97, the ascii code of ‘a’. cout << " "; }

cout<<(char)(x[0]-32); //’a’ is printed as ‘A’

in this code

using Ascii Table

When change these letter have to using Ascii Table

Explanation / Answer

#include<iostream.h>

void main(){

    char input[10];
    cout << "Enter String" << endl;
    cin >> input;
    for (int i = 0; i< 10; i++){
        if ( (input[i] > 96) && (input[i] < 123 )){
             input[i] = input[i] - 32;
        }
        if ( (input[i] > 64) && (input[i] < 91 )){
             input[i] = input[i] + 32;
        }

    }
    cout << input << endl;
}

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