The demand for subassembly S is 100 units in week 7. Each unit of S requires 2 u

Question

The demand for subassembly S is 100 units in week 7. Each unit of S requires 2 units of T and 2 units of U. Each unit of T requires 2 units of V, 1 unit of W, and 2 units of X. Finally, each unit of U requires 1 unit of Y and 3 units of Z. One firm manufactures all items. It takes 2 weeks to make S, 2 weeks to make T, 2 weeks to make U, 1 week to make V, 2 weeks to make W, 2 weeks to make X, 2 weeks to make Y, and 2 weeks to make Z. a) Choose the correct product structure. O B Level Level f) (2) w(1) 2) T(1) (3) O D. Leve Level U12) 1(2) T12) tr)

Explanation / Answer

Answer:- The correct option is:- Option A

Reason:- S has two child T and U both needing 2 units, so S will be divided into two branches which are T having 2 units and U having 2 units.

Now, T has three children namely V, W, and X, thus the sub-branch T will be divided into three sub-branches V having 2 units, W having 1 units and finally X having 2 units

Now, let us think of U, this will have two child branches namely Y and Z having 1 and 3 units respectively.

This figure is correctly represented by option A.

Answer:- The correct option is:- D

Reason:- As S has weeks time, thus the length of S will stretch from 5 weeks to 7 weeks.

S has two child branches namely T and U both requiring 2 week time. Thus S will be divided into two sub-branches T extending from 5 weeks to 3 weeks and U having length from 5 weeks to 3 weeks,

Now, T has Three children V having 1 week so it will extend from 3 weeks to 2 weeks, W having 2 weeks time thus extending from 3 weeks to 1 week and X having 2 weeks time, therefore, having the length from 3 weeks to 1 week.

Similarly is done for U.

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