Visual Basic. The question is how to make the program that takes in those values

Question

Visual Basic.

The question is how to make the program that takes in those values and yields an answer using their formula.

Geek Logik Dating and hell with her Romance in ou've been ogling her for the past status if you are in a relationship shame month to the on you go to the next equa The term point that your friends have finally given her a nickname E Kmakes sure your backgrounds matter, (the double-mochaccino hottie-hot- more or less depending on how well pants girl So what's stopping you from she knows you. If your backgrounds are making your move? Fear. And a nagging E compatible, your chances are best if she suspicion that the don't look good for knows you well, however, if the two of you odds you. Don't just sit there worrying, are completely incompatible you still have friend a chance as long she doesn't know it yet. Run the numbers. E Luckily, background can always be overcome The three sections of this equation weigh in order the first impression you E by the first set of terms-if you are witty, are likely to make with the compatibility of aggressive, and dashing (well, at least witty your backgrounds and with her relationship i and aggressive), there's always hope

Explanation / Answer

Since I am a c++ programmer, i would be solving your problem in c++.

#include<iostream>

using namespace std;

int main()
{
   int a1, a2, r, w, e1, e2, g, c1, c2, s1, s2, k;
   cin >> a1 >> a2 >> r >> w >> e1 >> e2 >> g >> c1 >> c2 >> s1 >> s2 >>k;
   int result=-1;
   int part1, part2;
   part1 = (w*g*a1*a1)/(a2*a2*a2);
   part2 = ((c1-c2)+((s1-s2)/100)+(e1-e2))/k;
   result=part1 + part2 - r;
   if(result<0)
       cout<<"lower your standards"<<endl;
   else if(result>=0 && result<=1)
       cout<<"you have exacty a snowball's chance"<<endl;
   else if(result>1 && result<=10)
       cout<<"game on"<<endl;
   else
       cout<<"you are too cute for her, go for her cute friend instead"<<endl;
   return 0;
}

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