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Assembly Language,,, i have a code,, i need to explain every line ,, what each l

ID: 3838555 • Letter: A

Question

Assembly Language,,,

i have a code,, i need to explain every line ,, what each line do and whats their function,,, Please answer me in a word document please,,,Explain each line please,,,,

page 55,80
.model small
.stack 100h
.386
.data
   msg1 db 0DH,0AH,"Enter any base from 2 to 35 ","$" ;
   num2 dd ?
   num1 dd ?
count db 0
num3 dd 10
.code
main proc
mov ax,@data ; set up data segment
mov ds,ax
        mov dx,offset msg1
mov ah, 9
int 21h

call enterkey
mov eax, ecx
mul num3
mov num2, eax

call enterkey
add num2,ecx
  
loop3:  
mov num1, 550  
   mov count, 0
  
call newline
loop1:
   mov eax, num1 ; copy num1 to EAX
mov edx, 0 ;edx = remainder = 0
div num2 ; EAX/NUM2
push dx ;saving the remainder to the stack
    inc count ;inc the counter for how many stack locations
mov num1, eax ;saving eax back to num1 since ah gets new value
   cmp num1, 0 ; checking if num1 = 0 for end of devide.
   jnz loop1

loop2:
   pop dx ; getting the number store in the stack
call display_chr ; calling the display proc.
   dec count ; dec the stack counter
   jnz loop2
mov dl, -8 ; sending open (
call display_chr
mov edx, num2 ; display the base
call display_chr
mov dl, -7 ; sending close )
call display_chr
dec num2
cmp num2, 1
jnz loop3
mov ax, 4c00h
int 21h
display_chr proc
   cmp dl, 10
js skip
add dl, 7
skip:
add dl, 30h ; ascii adjust back
   mov ah, 6 ; sending a single character to the screen
    int 21h
   ret
display_chr endp
newline proc
   mov ah, 6
  
   mov dl, 0dh ; CT
   int 21h
   mov dl, 0ah ; NL
   int 21h
   ret
newline endp
enterkey proc
   mov ecx, 0
mov ah, 1
   int 21h
   sub al, 30h
mov cl, al
ret
enterkey endp   
main endp
end main

Explanation / Answer

Page 55,80//An instruction is a statement that becomes executable when a program is assembled. •

Model .small//defines the memory model used like medium, stack,large etc

.stack 100k // reserve the 100 bytes for stack.org and current address to 100 h

.386//enables the assembly of nin privileged instructions for processor

.data//register are described by CPU store data or memory address

Msg1 dB // the msg is stored in directive

Num1 dB//directive is most widely used directives

Count dB 0//returns count value is zero

.code//begin the instructions

Main proc//the main procedure starts

Mov ax,@data// macro data mov to the 16 bit register

Mov ds,ax// data will mov to the data sigment register.

Mov DX,offset msg1//msg mov to data register

Mov ah,a// data moved to accumulator register.

Int 21h//interrupt handler

Call entrykey // call text wt we entered

Mov eax,ecx/ /data is moved from code reg to accumulator register

Mul num3//performs multiplication

Mov num2,eax//accumulator data is mov to num2

Call entry key // call inputs

Add num2,ecx// addition num2 value and code register data

Loop3:start loop condition

Mov num1,550//in num1 stores the 550 value

Mov count ,0//here count value is zero

Call new line// just print text in new line

Loop1 : loop started

Mov eax,num1// here 550 value is mov to accumulator register

Copy num1,eax//again eax valu is copy to num1

Mov edx,0//zero is mov to data register

Edx=reminder=0//now zero is stored in data register

Div num2=eax,num1//perform division operation

Push DX,store remember// here reminder value is stored in stack

Inc count// initially count is0 now count value is increased

Mov num1,eax// again data mov to num1

Cmp num1,0// compare num1 value have 0 r not

Jnz loo1//jump not equal to zero repeat loop1

Loop2:(here onwords not describe entair code critically mnemonic are explained)

Pop DX//delete the data from stack

Dec count // now count value is 1 decrement to 0

Mov DL,-8// register with 8 bit have signed value

Js skip// jump sign terminate loop

Ret// indicates the return procedure.

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