Implement a function that counts the number of negative integers in a two-dimens

Question

Implement a function that counts the number of negative integers in a two-dimensional array with 100 rows and 100 columns. The function takes a two-dimensional array of int and returns the number of negative numbers in it. A declaration of the function is shown below.
int countNegatives(int a[100][100]);
Implement a function that counts the number of negative integers in a two-dimensional array with 100 rows and 100 columns. The function takes a two-dimensional array of int and returns the number of negative numbers in it. A declaration of the function is shown below.
int countNegatives(int a[100][100]);

int countNegatives(int a[100][100]);

Explanation / Answer

int countNegatives(int a[100][100])
{
   int i,j,count=0;
for(i=0; i<100; i++)
for(j=0;j<100;j++)
{
if(a[i][j]<0)
{
count++;
}
}
    return count;
}

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