FINAL ENAM FALL 2017 MCT 3121 DR GROH-VERSIONB )016 034 oem C somples. mple D) s
ID: 384139 • Letter: F
Question
FINAL ENAM FALL 2017 MCT 3121 DR GROH-VERSIONB )016 034 oem C somples. mple D) samples sample O93 Comstruct Cntral Chart: A cotrot chart is sed to identify a proce B) iul variables Di assigned causes of variation A) sonmal causes of vation 10 9- Constrect a Centrel Char The control s,calculated as three standand eviation trom the sample eninply tha of the sample points ane expected to fall between th·ww.al lower aoouul linia. A)50% D) 354 LO 16-02 Evaluate aentery Tures and Days-el-Supply: CAA sells 2,000 dozen 5) eggs each day IC& As days-of-supply increases from 2 days to 5 days, what will B) locrease foom 4,000 to 10000 D) Cannut b·determined A) Reman the C Decreasc from 1,000 to 400 LO 10-02 Evaluste laeatory Turas and Days-of-Supply: CAAsells two kinds of andwiches egulan and deluse Each regular sandwich cots S1 to make and cach deluxe sandwich coss 52 to make Os average, C&A; has 5 regdar and 10 deluxe andwiches in inventory and 0 5 days-of-supply How many sandwiches do C&A; expect to sell each day A) 15 B) 100 CI 50 D) 30Explanation / Answer
1) UCL = 1.2
LCL = 0.9
Mean = 1
SD = 0.2
Process is not centered, so Process capability = Min((UCL-Mean)/(3*SD), (Mean-LCL)/(3*SD))
= Min((1.2-1)/(3*0.2), (1-0.9)/(3*0.2)) = Min(0.33,0.16) = 0.16
Ans A
2) C
It plots the value of sample means for each sample to check whether values are between UCL & LCL
3) D
The Normal causes of variation are those which are routine but assigned causes of variation are non-routine and must be controlled
4) C
It will comply to 6 sigma definition of 99.73% level
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