Need to solve it using code blocks for c for engineers Use a while loop to appro

Question

Need to solve it using code blocks for c for engineers Use a while loop to approximate the value of e^x up to n=10 using the formula below. After each iteration, print the updated terms using a tabular format illustrated below n, x^n, n!, e^x. The factorial of a nonnegative integer n is written as n! and is defined as n! = n(n -1) (n -2) ...1. Factorials are not built into C programming but can be calculated efficiently in the loop body. By definition, o!=1 and 1! = 1. For example, 5! = s*4*3*2*1 which yield 120 e^x = 1 + x/11 + x^2/2! + x^3/3! + ....+x^n/n! Your output should resemble the following for x=1/5. The data is neatly formatted in columns using the escape sequence. The approximation is most accurate for values nearest to zero.

Explanation / Answer

#include <stdio.h>

float eApprox(float x, int maxIter) {
  
    /* Initializing for first term */  
    int n=1;
    float xN = 1;
    int nFact = 1;
    float eX = 1;
    float prevTerm = 1;
    printf(" n x^n n! e^x ");  
    printf("%2d %2.6f %-10d %2.6f ", 0, xN, nFact, eX);

    /* from n=1 to n=10 */
    while (n <= maxIter) {
      
        float curTerm = prevTerm * (x/n);
        eX += curTerm;          
        xN *= x;
        nFact *= n;

       printf("%2d %2.6f %-10d %2.6f ", n, xN, nFact, eX);

       prevTerm = curTerm;
           n++;
    }
  
    printf(" e^%.6f = %.6f (approximated upto n = %d) ",x, eX, maxIter);
    return eX;
}

int main()
{
    eApprox(1.5, 10);  
    return 0;
}

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