Write a program in C++ that will accept command line options to use in the progr

Question

Write a program in C++ that will accept command line options to use in the program.

Command line option 1 will be the program name.
Option 2 (if used) will be ‘-p’ and that will print the keyword used in option 3.
Option 3 will be the keyword
Option 4 will be file input
Option 5 will be file output

Example:
with argv[2] (‘-p’)
./test -p KEYWORD input.txt output.txt

without argv[2]
./test KEYWORD input.txt output.txt

So, recap, argv[2] (if used) will print argv[3] (KEYWORD).
If not used, the command line will just take name of program, keyword, input, and output file names.

Explanation / Answer

Here is your program below: -

#include <iostream>
#include<string>
using namespace std;

int main ( int argc, char *argv[] )
{
if(argc == 4) {
        string programName = argv[0];
        string keyword = argv[1];
        string inputFileName = argv[2];
        string outputFileName = argv[3];
} else if(argc == 5) {
        string programName = argv[0];
        string keyword = argv[2];
        string inputFileName = argv[3];
        string outputFileName = argv[4];
        cout<<"Keyword is "<<keyword;
} else {
        cout<<"Wrong number of options.";
}

}

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