This is my code below. It outputs correctly for the example given above. However

Question

This is my code below. It outputs correctly for the example given above. However, the program will test with different lengths of vectors and that is where I am having trouble. Any help would be greatly appreciated.

#include <iostream>
#include <vector> // Must include vector library to use vectors
using namespace std;

int main() {
const int NUM_INPUT = 6;
vector<int> userInts(NUM_INPUT); // A vector to hold the user's input integers
unsigned int i;

  
/* Type your code here. */
for (i = 0; i < NUM_INPUT ; ++i) {
cin >> userInts.at(i) ;
}


for (i = NUM_INPUT-1 ; i > 0; --i) {
cout << userInts.at(i) << " ";
}
cout << endl;

return 0;
}

Write a program the reads a list of integers, and outputs those integers in reverse. The input begins with an integer indicating the number of integers that follow. For coding simplicity, follow each output integer by a space, even the last one. Ifthe input is 5 246 8 10, the output is: 1086 42 To achieve the above, first read the integers into a vector. Then output the vector in reverse.

Explanation / Answer

#include <iostream>
#include <vector>   // Must include vector library to use vectors
using namespace std;

int main() {
   //const int NUM_INPUT = 6; //This is not needed.
   vector<int> userInts; // A vector to hold the user's input integers
   int i, n, num; //Declaring supporting variables

   /* Type your code here. */
   cin>>n; //Reading length of vector
    for (i = 0; i < n ; ++i) {
      cin >> num; //Reading next integer
      userInts.push_back(num); //Pushing integer into the vectot
   }

    //Displaying in reverse
   for (i = n - 1 ; i >= 0; --i) {
      cout << userInts.at(i) << " ";
   }
   cout << endl;

   return 0;
}

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