Each number on telephone keypads, except 0 and 1, corresponds to a set of upperc

Question

Each number on telephone keypads, except 0 and 1, corresponds to a set of uppercase letters
as shown in this list:
2 ABC, 3 DEF, 4 GHI, 5 JKL, 6 MNO, 7 PQRS, 8 TUV, 9 WXYZ
Hence, a phone-number specification can include uppercase letters and digits. Write a function
called dial that takes as its input argument a char vector of length 16 or less that includes
only these characters and returns as its output argument the telephone number as a uint64.
Here is the input and output for one example of a call of the function:
Input: '1FUNDOG4YOU'
Output: 13863644968
You can assume that a phone number never starts with 0. If the input contains any illegal
characters, the function returns 0. You are not allowed to use the built-in function strrep.

my code

function out = dial(inp)
dig = '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ';
vec = '012345678922233344455566677778889999';
[~,idb] = ismember(inp,dig);
out = sscanf(vec(idb),'%lu');
end

can you fix my code?

Explanation / Answer

function num = dial(str) [r,c] = size(str); if r > 1 || c > 16 num = uint64(0); return end num = []; for i = 1:length(str) n = toNum(str(i)); if n > -1 num = strcat(num,num2str(n)); else num = uint64(0); return end end num = uint64(str2double(num)); function num = toNum(ch) num = -1; LEG = {'0','1','2ABC', '3DEF', '4GHI', '5JKL', '6MNO', '7PQRS', '8TUV', '9WXYZ'}; for i = 1:length(LEG(:)) if strfind(LEG{i},ch) > 0 num = i - 1; return end end

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