In python 3 I need to update the below script to produce the following output wh

Question

In python 3 I need to update the below script to produce the following output when a value is input.

example output:

Enter a integer between 1 and 1,000: 246

The factors of 246: 2 3 41

or

Enter a integer between 1 and 1,000: 264

The factors of 264: 2 2 2 3 1

My code as it sits:

#Global list of the first 11 prime numbers
prime11 = (2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31)

#main function that asks users for number from 1 to 1000 and displays then prime factors
def main():
    #get user input
    num = int(input('Enter a positive integer between 1 and 1,000: '))
    #call factor function to get and return prime factors
    factors(num)

    #Test cases
    factors(12)
    factors(82)
    factors(600)
    factors(566)
    factors(197)
    factors(864)
    factors(954)
    factors(321)

#factor finder function
def factors(num):
    #variable to store user number chosen
    n = num
    #create a list for the prime factors to go
    ftrs = []
    #validate input
    if n <=1000 and n >=1:
        #loop through primes
        for i in prime11:
            # if one of them works
            while n % i == 0:
                #add it to list
                ftrs.append(i)
                #divide value and loop again
                n = int(n/i)
        #when value will no longer divide
        if n % i != 0:
            if n != 1:
                #add it factor list
                ftrs.append(n)
            else:
                 pass
        #clean the factor list up
        ftrs.sort()
        #print it out
        print(' The factors of %d:' % num, str(ftrs)[1:-1], ' ')
    #if bad data tell user
    else:
        print('Integer must be between 1 and 1,000.', ' ')

#call main
main()

Explanation / Answer

NOTE: I have modified your code so it can print the output in required format

Code:
#!/usr/local/bin/python3

#Global list of the first 11 prime numbers
prime11 = (2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31)

#main function that asks users for number from 1 to 1000 and displays then prime factors
def main():
#get user input
num = int(input('Enter a positive integer between 1 and 1,000: '))
#call factor function to get and return prime factors
factors(num)

#factor finder function
def factors(num):
#variable to store user number chosen
n = num
#create a list for the prime factors to go
ftrs = []
#validate input
if n <=1000 and n >=1:
#loop through primes
for i in prime11:
# if one of them works
while n % i == 0:
#add it to list
ftrs.append(i)
#divide value and loop again
n = int(n/i)
#when value will no longer divide
if n % i != 0:
if n != 1:
#add it factor list
ftrs.append(n)
else:
pass
#clean the factor list up
ftrs.sort()
#print it out
print(' The factors of %d: ' % num, end='')
for i in range(0, len(ftrs)):
print(ftrs[i], end=' ')
print(' ')
#if bad data tell user
else:
print('Integer must be between 1 and 1,000.', ' ')

#call main
main()

Execution and output:
Unix Terminal> python3 primef.py
Enter a positive integer between 1 and 1,000: 246
The factors of 246:2 3 41

Unix Terminal> vi primef.py
Unix Terminal> python3 primef.py
Enter a positive integer between 1 and 1,000: 246
The factors of 246: 2 3 41

Unix Terminal> python3 primef.py
Enter a positive integer between 1 and 1,000: 264
The factors of 264: 2 2 2 3 11

Unix Terminal> python3 primef.py
Enter a positive integer between 1 and 1,000: 100
The factors of 100: 2 2 5 5

Unix Terminal> python3 primef.py
Enter a positive integer between 1 and 1,000: 299
The factors of 299: 13 23

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