THIS IS IN C Write a function double sum_sequence (int n) that calculates and re

Question

THIS IS IN C

Write a function double sum_sequence (int n) that calculates and returns the sum 1/1 - 1/2^2 + 1/3^3 - 1/4^4 + 1/5^5 - 1/6^6 + middot middot middot + 1/(2n - 1)^2n - 1 - 1/(2n)^2n where n is a positive integer argument passed to the function. For example. sum_sequence (3) should return the value (1/1)- (1/4) + (1/27)-(1/256) + (1/3125) - (1/46656) = 0.7834. Your function should be written bearing in mind the limitations on computer-implemented arithmetic that were discussed through the semester. You may not make use of any functions from math. h in this question.

Explanation / Answer

#include <stdio.h>
double sum_sequence( int n)
{   float term,   term1,term2 ;int i;
term2= 1;
for (i=0;i<2*n;i++)
term2= term2/(2*n);
term1= 1;
for (i=0;i<2*n-1;i++)
term1= term1/(2*n-1);

if (n==1) return 0.75;
else{
return term1-term2+sum_sequence(n-1 ) ;
}
  
}
int main()
{
double sum;
int n;

n = 2;
sum = sum_sequence( n) ;

printf("sum=%f ",sum);
    printf("Hello, World! ");

    return 0;
}

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