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Write a program named ProcessArray.java, and write two static methods as specifi

ID: 3854552 • Letter: W

Question

 Write a program named ProcessArray.java, and write two static methods as specified in the following header:  public static int[] oddArray(int[] arr) public static int[] evenArray(int[] arr)  the oddArray method returns a sorted (in ascending order) array that contains all odd numbers in the argument array, and the evenArray method returns a sorted array that contains all even numbers in the argument array.  For example,   int[] arr={ 3, 8, 1, 9, 2};  ProcessArray.oddArray(arr) should return {1,3,9} ProcessArray.evenArray(arr) should return {2,8}  KEEP ALL OF THE NAMES AS THEY ARE 

Explanation / Answer

The java programming code is ,the name of the program is ProcessArray.java

package constructors;

import java.util.*;

public class ProcessArray

{

public static void main(String[] args) {

int[] arr = {3, 8, 1, 9, 2};

int[] res;

System.out.println(Arrays.toString(arr));

selectionSort(arr);

System.out.println(Arrays.toString(arr));

res = ProcessArray.oddArray(arr);

System.out.println(Arrays.toString(res));

res=ProcessArray.evenArray(arr);

System.out.println(Arrays.toString(res));

}

//method to sort numbers in an array

private static void selectionSort(int[] arr) {

// TODO Auto-generated method stub

for (int i = 0; i < arr.length - 1; i++) {

int index = 0;

for (int k = 0; k < arr.length - i; k++) {

if (arr[k] > arr[index]) {

index = k;

}

}

//swapping

int tmp = arr[index];

arr[index] = arr[arr.length - 1 - i];

arr[arr.length - 1 - i] = tmp;

}

}

//method to take array of odd numbers

public static int[] oddArray(int[] arr) {

int c = 0;

for (int i = 0; i < arr.length; i++) {

if (arr[i] % 2 != 0) {

c++;

}

}

int[] arrayc = new int[c];

int ins=0;

for (int i = 0; i < arr.length; i++)

if (arr[i] % 2 != 0)

arrayc[ins++]=arr[i];

return arrayc;

}

//method to take array of even numbers

public static int[] evenArray(int[] arr) {

int c = 0;

for (int i = 0; i < arr.length; i++) {

if (arr[i] % 2 == 0) {

c++;

}

}

int[] arrayc = new int[c];

int ins=0;

for (int i = 0; i < arr.length; i++)

if (arr[i] % 2 == 0)

arrayc[ins++]=arr[i];

return arrayc;

}

}

the output is:[3, 8, 1, 9, 2]
[1, 2, 3, 8, 9]
[1, 3, 9]
[2, 8]

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