Using visual studio and the program code below, modify the program code so the o

ID: 3856302 • Letter: U

Question

Using visual studio and the program code below, modify the program code so the out put will display a graph line using the information given to you below:

When the switch shown in Figure 7.14 is closed at time t = 0, the voltage, V, across the capacitor, C, is given by this formula:

V = E(1 - e-t/RC)

E is the voltage of the battery.

R is the resistance in the circuit.

C is the value of the capacitance.

e is Euler's number (2.71828 . . .).

t is the time in seconds

Assuming E = 50, R = 4000, and C = 0.005, modify Program 7.13 to plot the voltage across the capacitor from t = 0 to t = 60 in increments of 2 seconds.

Program7.13

#include

using namespace std;

int main()

{

const int MAXPOINTS = 100;

int i, npts, nval[MAXPOINTS];

double x, fval, ymin, ymax, width, sval[MAXPOINTS];

char label[] = " y axis";

char axis[] = "+---------------------------------------------------->";

char line[] = "| ";

ymax = 1.0e-5;

ymin = 1.0e5;

width = 53;

// load the data to be plotted and find the max and min values

i = 1;

for(x = -5.0; x <= 5.0; x += 0.5)

{

sval[i] = pow(x,3.0);

if (sval[i] > ymax) ymax = sval[i];

if (sval[i] < ymin) ymin = sval[i];

i++;

if (i >= MAXPOINTS) break; // don't exceed the maximum points

}

npts = i - 1;

// scale all the y values

for (i=1; i <= npts; i++)

{

fval = (sval[i] - ymin)/(ymax - ymin) * (width - 1) + 1;

nval[i] = fval + 0.5; // convert to an integer value

}

// produce the plot

cout << "Minimum y value: " << ymin << endl;

cout << "Maximum y value: " << ymax << endl;

cout << label << endl;

cout << axis << endl;

for (i = 1; i <= npts; i++)

{

line[(nval[i] + 2)] = '*'; // set character to an asterisk

cout << line << endl; // output the line

line[(nval[i] + 2)] = ' '; // reset character to a blank

}

return 0;

}

Switch E Figure 7.14 a simple RC circuit

Explanation / Answer