solve question three the answers which I\'m not sure I did wright I\'m not sure
ID: 3856637 • Letter: S
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solve question three the answers which I'm not sure I did wright I'm not sure in front of it
The 8086 was divided into two main parts. The was the "brain" of the processor, and had the ALU, general-purpose register, control unit, and flags, The contained the segment registers, uddress udder, instruction pre-fetch queue, and handled all the interfacing to memory and I/O. The 8086 used real-mode addressing, which means that the multiplying the adding the contents of the address of a memory location si found by register by 1610 (or 01016) and thern register. For example, if SP contains 021Cro and SS contains 2A38to, the actual real mode address being accessed is hex 4 (general fill-in-the-blanks... The 8086 and its descendants have one data bus and one address bus, implying that memory and I/O share the same data bus and address bus. Whether an access is intended for memory or VO is determined by bits such as so, si , and S2 (for example). The 8086 assembler, , is -- converts the user assembly language program into which the processor understands. This assembler uses the symbol to identify a label used in the code segment, and a symbol to denote that the rest of the line (to the right of the symbol) is a comment. Intel x86 assembly language instructions have an , which is an action, and from 0 to 3 which specify the objects that the action takes place on. The first object is the ( source / destination circle one), while the remaining objects form the (source / destination circle one). The rules for these objects are that they must be ( different sizes / the same size /source must be smaller than the destination circle one, and both source and destination can't be To clear a register such as BX in x86 assembly code, the best method is to use the instruction because (arithmetic/looping/CX register/logical circle one) instructions are more efficient. This type of instruction is betterExplanation / Answer
The 8086 was divided into two main parts. The EU was the "brain" of the processor, and had the ALU, general-purpose registers, control unit, and flags.
The BIU contained the segment registers, address adder, instruction pre-fetch queue, and handled all the interfacing to memory and I/O.
The 8086 used real-mode addressing, which means that the Physical Address of a memory location SI found by multiplying the Segment register (CS, SS, DS, ES) by 1610 (or 01016) and then adding the contents of the Offset register (IP, BX, SI, DI, SP, BP). For Example, if SP contains 021C16 and SS contains 2A3816, the actual real mode address being accessed is 2A59C hex (10h*2A38h + 021Ch = 2A59Ch).
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