Much help would be appreciated! ? What is the network address for AP1PA? A) 192.

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Much help would be appreciated!

?

What is the network address for AP1PA? A) 192.168.0.0/24 B) 172.16.0.0/16 C) 10.0.0.0/8 D) 169.254.0.0/16 You have an IP address with a Classless InterDomain Routing (C1DR) notation of/26. What is the dotted-decimal form of the subnet mask? A) 255.255.255.128 B) 255.255.255.224 C) 255.255.255.0 D) 255.255.255.192 You have a subnet mask of 255.255.255.248, what is the Classless InterDomain Routing (CIDR) notation? A)/26 B)/29 C)/27 D)/28 How many subnets do you get with a subnet of 10.0.1.0/27? A) 13 B)8 C) 20 D) 12 How many hosts can you have with a subnet of 192.168.1.0/29? A) 30 B) 7 C) 8 D) 6 The strength of the electromagnetic waves being radiated from an antenna is referred to as gain, which involves a measurement of both direction and efficiency of a transmission. Gain is commonly measured using the dBi unit of measure. A) True B) False Which of the following wireless standards operate at a Maximum Bandwidth of less than 20Mbps? A) 802.11g B) 802.11b C) 802.11a D) 802.11 The image below represents what type of warchalking symbol? A) WEP node B) Open node C) Paid node D) Closed node To protect WLAN traffic from eavesdroppers, a variety of security standards and practices have been developed, including all of the following except: A) Preshared key B) Enabling SSID broadcast C) MAC address filtering D) IEEE 802.1 X Which of the following is NOT a WLAN security standard? A) WPA B) WEP C) WAP D) WPA2 An omnidirectional antenna radiates power at relatively unequal power levels in all directions (somewhat similar to the theoretical isotropic antenna). A) True B) False The___command can be used to see what a Layer 2 MAC address corresponds to a known Layer 3 IP address. A) MAC B) ARP C) pathping D) netstat

Explanation / Answer

8) D

Automatic Private IP Addressing (APIPA) is the windows function to provide DHCP autoconfiguration addressing. APIPA assigns ip addresses from class B that starts from 169.254.0.0 to 169.254.255.255

9) D

                Given CIDR notation is /26.

                That means 26 bits are one’s in the mask and remaining (32-26=6 bits ) are 0’s

                1 1 1 1 1 1 1 1 . 1 1 1 1 1 1 1 1 . 1 1 1 1 1 1 1 1 . 1 1 0 0 0 0 0 0

                Now convert each octant into Decimal

                255 . 255 . 255 . 192

                This is the subnet mask for CIDR notation /26

10) B

                The given subnet mask is 255.255.255.248

                Now convert it into binary notation

                1 1 1 1 1 1 1 1 . 1 1 1 1 1 1 1 1 . 1 1 1 1 1 1 1 1 . 1 1 1 1 1 0 0 0

                Now count no of 1’s

                i.e 29.

                The CIDR notation is /29

11) B

                The given IP is 10.0.1.0/27

                10.0.1.0 -              0 0 0 0 1 0 1 0 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 1 . 0 0 0 0 0 0 0 0

                                                                The mask will be /24

                /27                         -              1 1 1 1 1 1 1 1 . 1 1 1 1 1 1 1 1. 1 1 1 1 1 1 1 1 . 1 1 1 0 0 0 0 0

                27 – 24 = 3

                2^3 = 8 sub nets are possible.

12) D

                Given IP is 192.168.1.0/29

                29 bits are network bits and the remaining (32-19) 3 bits are the host bits.

                2^3 (8) IP addresses are available.

                But 2 bits are not used for host (first IP as network address and last IP as broadcast). So subtract those two IP addresses.

                8 – 2 = 6 hosts

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