Write a single 16-bit LC-3 instruction (in binary) that doubles the value in R3

Question

Write a single 16-bit LC-3 instruction (in binary) that doubles the value in R3.

Write a single 16-bit LC-3 instruction (in binary) that clears all the bits of R6 except the least significant two bits.

In other words, after your instruction executes, bits 0 and 1 of R6 will be unchanged, and the rest of R6 will be zero.

Write a single 16-bit LC-3 instruction (in binary) that doubles the value in R3. Answer: Write a single 16-bit LC-3 instruction (in binary) that clears all the bits of R6 except the least significant two bits In other words, after your instruction executes, bits 0 and 1 of R6 will be unchanged, and the rest of R6 will be zero. y 10.

Explanation / Answer

1)

You want to double the value in R3 so we add them and store in the same R3.

add R3,R3,R3;

2)

AND R6 , R6, 0003

here 0003 in hexadecimal.

here 0003 = 0000 0000 0000 0011 so that after doing AND with R6 it will give you last 2 bit as same as in R6 and other bits as 0

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