Need Help!! #1 answer is D and #2 answer is C, Please explain why. Figure) 1) Co

Question

Need Help!!

#1 answer is D and #2 answer is C,

Please explain why.

Figure)

1) Consider the information in Figure 2. What are the first and last addresses of the bytes stored in the data field at index 9?

A) 00000028 and 00000037 (hexadecimal)

B) 00000280 and 0000028F (hexadecimal)

C) 00002890 and 0000289F (hexadecimal)

D) 00028900 and 000289FF (hexadecimal)

E) None of the above.

2) Consider the information in Figure. Assume that the current program sends the address FF987654 (hexadecimal) to the data cache. To which cache slot is that address mapped?

A) Slot 4

B) Slot 5

C) Slot 6

D) Slot F

E) None of the above.

A microprocessor has 32-bit physical addresses The data cache is a direct mapped, write-back cache with 16 slots The control bits for each slot are a valid bit (V) and a modified bit (M) A cache block is 256 bytes. The current cache entries are shown below (in hexadecimal) For clarity the 256-byte data blocks are not shown Index v M Tag Index v M Tag 1 0 FF641 0 0 0 0 04A 1 0 00014 1 0 00028 1 0 000 3A 1 0 00028 1 FF593 1 1 FFF 7C 1 FFF 7C 0 1 00EA1 1 0 00014 1 0 00028 1 0 00014 1 1 000 3A 1 0 00014 1 000 3A

Explanation / Answer

1.Consider the information in Figure 2 is 00000280 and 0000028F addresses of the bytes stored in the data field at index 9.

2. the current program sends the address FF987654 to the data cache. Slot 6 cache slot is that address mapped.

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