The concentration of a drug in the body, Cp, can be modeled by the equation: Cp

Question

The concentration of a drug in the body, Cp, can be modeled by the equation:

Cp = (Dg/Vd)(ka/(ka-ke))(e^(-ke t)-e^(-ka t))

where Dg is the dosage administered in mg, Vd is the volume of the distribution in liters, ka is the absorption rate of the drug into the body in 1/hour, ke is the body's elimination rate of the drug from the body also in 1/hr, and t is the time in hours since the drug was administered.

Problems Set 7 Set 7 No 3 Problem Description The concentration of a drug in the body, Cp, can be modeled by the equation: Cp (DgNd)(ka/(ka-ke) (en (-ket)-en (-kat)) where Dg is the dosage administered in mg, Vd is the volume of the distribution in liters, ka is the absorption rate of the drug into the body in 1/hour, ke is the body's elimination rate of the drug from the body also in l/hr, and t is the time in hours since the drug was administered Create a script file that uses a for loop to calculate the concentration of four, 6 hour doses of a drug over a 24 hour period every 6 minutes (0.1 hours) given that Dg 250 mg, Vd 50 L, ka 0.8 a hn-1, and ke30.25 hn-1 Solution MATLAB Documentation 1 Use a for loop with a nested if statement to solve this problem

Explanation / Answer

Answer:-

Matlab code:-

Note:- code is explained with comments followed by %

% initializing given values of Dg, Vd, ka and ke
Dg=250;
Vd=50;
ka=0.8;
ke=0.25;

for t=1:0.1:24 % loop for time = 1 to 24 hours every 0.1 hour
if mod(t,6)==0 % since the concentration is asked for four 6 hour doses i.e for 6,12,18,24 hours
Cp = (Dg/Vd)*(ka/(ka-ke))*(exp(-ke * t)-exp(-ka * t)) % expression to caluculate Cp (concentration) and print it's %value
end
end
  
  Output :-

>> conc

Cp =

1.5629

Cp =

0.3616

Cp =

0.0808

Cp =

0.0180

Therefore the concentration of drug at 6,12,18,24 hours is 1.5629,0.3616,0.0808 and 0.0180 respectively.

,

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.