Add comments to explain each line of the program and briefly explain the purpose
ID: 3865185 • Letter: A
Question
Add comments to explain each line of the program and briefly explain the purpose of the program. Determine the values of the symbols ‘main’, ‘bound’, ‘ipt’, and ‘loop’.
BR main
bound: .EQUATE 10
ipt: .EQUATE 0
main: SUBSP 2, i
DECI ipt, s
loop: LDWA ipt, s
CPWA bound, i
BRGE endloop
ADDA 1, i
STWA ipt, s
DECO ipt, s
LDBA ' ', i
STBA charOut, d
BR loop
endloop: ADDSP 2, i
STOP
.END
Explanation / Answer
BR main. //BR is branch with return value,it goes to label main
bound: .EQUATE 10 //bound will check array index bound I.e.,size is 10,stack size is 10
ipt: .EQUATE 0 //index starts from 0,stack pointer is at index 0
main: SUBSP 2, i //SUBSP=SP-operand ,i.e.,SP is a stack pointer that subracts i from the stack by popping 2 bytes
DECI ipt, s //decimal input I.e.,ASCII value of s is 115
loop: LDWA ipt, s //push 115 at stack pointer index of ipt i.e.,0
CPWA bound, i //value at index i is copied to index 10
BRGE endloop //BRGP is brach if greater than or equal to (checks bound>=ipt)
ADDA 1, i //Adds 1 to the value at index i and stores the result in i
STWA ipt, s //stores value at index s in address i
DECO ipt, s //DECO is decimal output i.e.,stores 115 at input pointer i
LDBA ' ', i //loads empty space(' ') at index i
STBA charOut, d //stores operand d from symbolic table
BR loop //executes loop ,until bound>=ipt
endloop: ADDSP 2, i //pushes operand i to stack by pushing 2 bytes
STOP //stops the execution
.END
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