Use Python 3 for the following question: Write a program that determines all six

Question

Use Python 3 for the following question:

Write a program that determines all six-digit numbers SLAYER (where each letter stands for the digit in the position shown) where the following equation true: SLAYER + SLAYER + SLAYER-LAYERS. For example, one number which satisfies this is 142857. The program should print out the above equation for each solution. Sample output: 142857 + 142857 + 142857 = 428571 HINT: Although there may be some way to methodically solve the puzzle, it is by far easier to just brute force it by checking every single possibility. The itertools.permutations function can give you each permutation of the digits (19,

Explanation / Answer

The below code satisfies the given requirements as follows:-

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print('The requirend output :')

for num1 in range(100000,999999) : #the loop iterates for all 6 digit numbers

dig = []

dig = list(int(d) for d in str(num1)) #converting the given number into array format

temp=dig[0]

dig.pop(0)

dig.append(temp)

num2 = map(str, dig)

num2 =''.join(num2)

num2 = int(num2) #num2 will contains the LAYERS value

temp = num1 + num1 + num1

dig2=[]

if temp==num2: #this if loop justifies whether the given value is come under the given equation

dig2.append(num1)

print('{0} '.format(dig2[0]))

Output:-

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The requirend output :

142857

285714

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