The Pentium 4 Prescott processor, released in 2004, had a clock rate of 3.6 GHz
ID: 3871136 • Letter: T
Question
The Pentium 4 Prescott processor, released in 2004, had a clock rate of 3.6 GHz and voltage of 1.25 V. Assume that, on average, it consumed 10 W of static power and 90 W of dynamic power.The Core i5 Ivy Bridge, released in 2012, had a clock rate of 3.4 GHz and voltage of 0.9 V. Assume that, on average, it consumed 30 W of static power and 40 W of dynamic power. The Pentium 4 Prescott processor, released in 2004, had a clock rate of 3.6 GHz and voltage of 1.25 V. Assume that, on average, it consumed 10 W of static power and 90 W of dynamic power.
The Core i5 Ivy Bridge, released in 2012, had a clock rate of 3.4 GHz and voltage of 0.9 V. Assume that, on average, it consumed 30 W of static power and 40 W of dynamic power. The Pentium 4 Prescott processor, released in 2004, had a clock rate of 3.6 GHz and voltage of 1.25 V. Assume that, on average, it consumed 10 W of static power and 90 W of dynamic power.
The Core i5 Ivy Bridge, released in 2012, had a clock rate of 3.4 GHz and voltage of 0.9 V. Assume that, on average, it consumed 30 W of static power and 40 W of dynamic power.
Explanation / Answer
1) The average capacitive load for both of the precessors is given by the formula:
Capacitive load = Dynamic power / (0.5 * V2 * Clock rate)
For Pentium 4 Prescoott Processor, Capacitive Load = 90 / ( 0.5 * (1.25)2 * 3.6 * 109) (since 1 GHz - 109 Hz)
= 3.2 * 10-8
For Core i5 , Capacitive load = 40 / (0.5 * (0.9)2 * 3.4 * 109)
= 2.904 * 10-8
So, we can see that the capacitive load on the core i5 processor is less than that of the Pentium 4 Prescoot processor.
2) Ratio of the static power to the dynamic power for each of the technology is given as:
For Pentium 4 Prescoot processor.: Static power / Dynamic Power
= 10 / 90 = 0.11
For core i5: Static power / Dynamic Power
= 30 / 40
= 0.75
As, the question is not completely mentioned, still I've covered the neccessary concepts through numerical computations.
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