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This needs be written in javascript. All i need help with is creating the variab

ID: 3871550 • Letter: T

Question

This needs be written in javascript. All i need help with is creating the variables and the functions to figure out the solution. The instructions are below.

Create a function that starts with a date and a number of days to add to date

in order to generate an end date.

Create an IIFE

(function () {

// logic here

})();

/* Need to know

- how many days in each month

- is it a leap year

       - Option: keep leap years in array

        - Option: base year and figure learp years from that

        - Option: year divisible by 4 but not 100(see function below)

function leapYear(year)

{

    return ((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0);

}

Step 1: Get the day of the date

Step 2: Add number of days value

Step 3: Compare new balue with end of month

Step 4: Keep if before or on the last day of month

Step 5: Get number of days past last day of month

Step 5a: Increment month (check for Dec)

Step 5b: Set month to Jan and increment year if Dec

// Create a variable called thisDate using explict year (2017), month (September), and day (26) - OCT 11

var startDate = new Date(2017, 08, 26);

var daysToAdd = 15;

Explanation / Answer

function myFunction() {

var year = 2007;

var month = 11;

var day = 5423;

var startDate = new Date(year, month, day);

document.getElementById("demo1").innerHTML = startDate;

var daysToAdd = 6;

var day_in_months = [ 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31];

  

while(daysToAdd >= 366){

if(leapYear(year+1)){

daysToAdd -= 366;

}else{

daysToAdd -= 365;

}

year +=1;

}

var total_days = day + daysToAdd;

  

  

while( (leapYear(year) && month==1 && total_days >= 29) ||

total_days >= day_in_months[month]){

if(leapYear(year) && month == 1){

total_days -= 29;

month += 1;

}

else{

total_days -= day_in_months[month];

  

if(month == 12){

month = 1;

year +=1;

}else{

month +=1;

}

}

}

var endDate = new Date(year, month, total_days);

return endDate;

}

function leapYear(year)

{

return ((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0);

}

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