In c++ program .111 69% 13:07 PM Write a program to model a simple calculator. E

Question

In c++ program

.111 69% 13:07 PM Write a program to model a simple calculator. Each data line should consist of the next operation to be performed from the list below and the right operand. Assume the left operand is the accumulator value (initial value of 0). You need a function scan_data with two output parameters that returns the operator and right operand scanned from a data line. You need a function do_next op that performs the required operation. do_next op has two input parameters (the operator and operand) and one input/output parameter (the accumulator). The valid operators are: + add subtract multiply divide power (raise left operand to power of right operand)

Explanation / Answer

#include<iostream>
#include<string.h>
#include<stdlib.h>
#include<math.h>

using namespace std;

void scan_data(char &opr, string &data){
    cin >> opr >> data;
}

void do_next_op(char opr, string data, double &acc){
     
     double res;
     double res1;
     int type = 0;
    
     for (int i = 0; i<data.size(); i++){
        if (data[i] == '.'){
            type = 1;
            break;
        }
     }

     if (atoi(data.c_str()) != 0 && type == 0){
       
         res = atoi(data.c_str());
         if (opr == '+'){
            acc = acc + res;
         }
         else if (opr == '-'){
            acc = acc - res;
         }
         else if (opr == '*'){
              acc = acc * res;
         }
         else if (opr == '/'){
           if (res == 0){
              cout << "Error: division by zero" << endl;
           }
           else {
                acc = acc/res;
           }

         }
         else if (opr == '^'){
             acc = pow(acc,res);
         }
         else {
          cout << "Error: invalid operator ";
         }
        
     }
     else if (atof(data.c_str()) != 0 && type == 1){
         res1 = atof(data.c_str());
         if (opr == '+'){
            acc = acc + res1;
         }
         else if (opr == '-'){
            acc = acc - res1;
         }
         else if (opr == '*'){
              acc = acc * res1;
         }
         else if (opr == '/'){
           if (res == 0){
              cout << "Error: division by zero" << endl;
           }
           else {
                acc = acc/res1;
           }

         }
         else if (opr == '^'){
             acc = pow(acc,res1);
         }
         else {
          cout << "Error: invalid operator ";
         }

     }
     else {
         cout << "Error: invalid operand ";
        
     }
     cout << "Result so far is " << acc << endl;
}

int main(){
  
   char opr;
   string data;
   double acc;
   acc = 0;
  
   do {
       scan_data(opr,data);
       if (opr != 'q' || data != "0")
          do_next_op(opr,data,acc);
      
   } while (opr != 'q' || data != "0");
   return 0;
}

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