write a C programming that can run like this to find the rainfall data of 6 week

Question

write a C programming that can run like this to find the rainfall data of 6 weeks with the data inported from a text file. do not use array. Notice that it's possible for the result to have two different days or week.

Daily Rainfal Total Week #1: 3 0 0 7 821 0 39mm Week #2 : 0 1 1 0 0 0 4 6mm Week #3: 9672000 24mm Week #4 : 0000013 4mm wee Week #6 : 1 0 1 0 0 0 0 2mm 0mm Total rainfall: 75mm (an average of 12.5mm per week) Driest week: 5 Wettest week: 1 Total rainfall on driest day of week: 7mm Con Monday, Saturday) Total rainfall on wettest day of week: 22mm Con Friday) liberty: ~/tmp/%

Explanation / Answer

#include<iostream>

#include <iomanip>

using namespace std;

// Constant for the number of months

const int NUM_MONTHS = 12;

// Function prototypes

double getTotal(double [], int);

double getAverage(double [], int);

double getLargest(double [], int, int &);

double getSmallest(double [], int, int &);

double getTotal(int rainFall,double NUM_MONTHS[])

{

double total = 0;

for (int count = 0; count < NUM_MONTH; count++)

total += NUM_MONTH[count];

return total;

}

double getAverage(int rainFall,double NUM_MONTH[])

{getTotal(rainFall,NUM_MONTH)

average= total/NUM_MONTHS;

return average;

}

double getHighest(int rainFall, double NUM_MONTHS[]) //I left out the subScript peice as I was not sure how to procede with that;

{

double largest;

largest = NUM_MONTHS[0];

for ( int month = 1; month <= NUM_MONTHS; month++ ){

                      if ( values[month] > largest ){

                  largest = values[month];

return largest;

             }

double getSmallest(int rainFall, double NUM_MONTHS[])
046
{

double smallest;

smallest = NUM_MONTHS[0];

for ( int month = 1; month <= NUM_MONTHS; month){
                      if ( values[month] < smallest ){
                  smallest = values[month];
return smallest;

             }
   
int main()
{
   // Array to hold the rainfall data
   double rainFall[NUM_MONTHS];

   // Get the rainfall for each month.
or (int month = 0; month < NUM_MONTHS; month++)

// Get this month's rainfall.

cout << "Enter the rainfall (in inches) for month #";

      cout << (month + 1) << ": ";

      cin >> rainFall[month];

     

      // Validate the value entered.

      while (rainFall[month] < 0)

      {

         cout << "Rainfall must be 0 or more. "

              << "Please re-enter: ";

         cin >> rainFall[month];

      }

   }

  

   // Set the numeric output formatting.

   cout << fixed << showpoint << setprecision(2) << endl;
  

   // Display the total rainfall.

   cout << "The total rainfall for the year is ";

   cout << getTotal(rainFall, NUM_MONTHS)

        << " inches." << endl;

   // Display the average rainfall.

   cout << "The average rainfall for the year is ";

   cout << getAverage(rainFall, NUM_MONTHS)

        << " inches." << endl;
   // Now display the largest & smallest amounts.

   // The subscript variable will be passed by reference

   // the the getLargest and getSmallets functions.

   int subScript;

   // Display the largest amount of rainfall.

   cout << "The largest amount of rainfall was ";

   cout << getLargest(rainFall, NUM_MONTHS, subScript)

        << " inches in month ";

   cout << (subScript + 1) << "." << endl;

   // Display the smallest amount of rainfall.

   cout << "The smallest amount of rainfall was ";

   cout << getSmallest(rainFall, NUM_MONTHS, subScript)

        << " inches in month ";

   cout << (subScript + 1) << "." << endl << endl;

   return 0;

}
     

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