so by doing this problem over and over again i finally got the right answer but

Question

so by doing this problem over and over again i finally got the right answer but could someone write the code that proves this in matlab ?

Question 6 5/ 5 pts We wish to find a solution using an iterative technique. Using a supplied function we wish to achieve a solution that changes less than 0.01% between iterations. Review the relevant sections of the code shown below and determine what is the value of es that we should input the function. function [out] “ iterati ini, in2, e, maalt, tor 1-11100 ea -aba inew-old)/new it ea es,break, end end Corect 0.0001 0.01 0.001

Explanation / Answer

The main aim of the question is to find the value of es.

es = 0.01% = 0.01/100= 0.0001

To verify the statement of question,

You can consider the example of newton rapsion methode. When the change in root becomes smaller than es, we stop the program and output value of root.

Matlab code:

function [out] = iterative(in1, in2 ,es,maxIt)

syms a;

func = @(x) (3*(x^3) - 6*(x^2) + 4*x - 8/9); %define the function

x= 2; %initial guess

tmp(1) = in1;

g = matlabFunction(diff(func(a),a)); % derivative of function

h = (func(x))/ (g(x));

i = 1;

while(abs(h) > es & i< maxIt)

h = func(x)/ g(x);

x = x - h; % update value of root  

i=i+1;

end

root = x % final value of root

out = root;

end

Sample Output:

>> iterative(2,3,0.0001,100)

root =

0.6668

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