Assemble the following assembly-language code by writing out the corresponding m

Question

Assemble the following assembly-language code by writing out the corresponding machine language instructions. You may find instruction definitions in Appendix A or in the Wikipedia article on MIPS. The hex address of each instruction is given to the left of each instruction. Print this page and fill in the decimal values for each field, convert to binary, and then convert the whole instruction to hexadecimal. The first one is done for you as an example. For longer fields, such as the immediate data in I-type instructions, draw a line connecting the fields, such as 6. 4000 slt Ss1, Ss2, Ss3 Instruction breakdown by binary bit 5 bits 6 bits 4 2 5 bits 5 bits 5 bits 6 bits Dec Bin lol0lolo 0 0 10 0101 01011100 0 10000 0 101 0 10 Hex 8 8 2 2 4004 or $s1, $s2, $s3 Instruction breakdown by binary bit 5 bits 5 bits 5 bits 5 bits 6 bits 6 bits Dec Bin Hex 4008 addi $to, $t4,17 Dec Bin Hex 400C add $s1, $s1, $s3 Dec Bin Hex 4010 sw $s0, 100($t2)#100 is a decimal number Dec Bin Hex

Explanation / Answer

6.:

or $s1, $s2, $s3

R type instruction:

Most significant 6 bits corresponds to r type: 000000

least significant 6 bits corresponds to or instruction: 100101

rs = $s2 = 10010, rt = $s3 = 10011, rd = $s1 = 10001, shamt = 00000

Binary = 000000 10010 10011 10001 00000 100101

Decimal = 0 18 19 17 0 37

HexaDecimal = 0 2 5 3 8 8 2 5 = 0x02538825

addi $t0, $t4, 17

I type instruction:
Most significant 6 bits corresponds to addi = 001000

rs = $t4 = 01100

rd = $t0 = 01000

17 is in 16 bits: 0000 0000 0001 0001

Binary = 001000 01100 01000 0000000000010001

Decimal = 8 12 8 ---17---

Hexadecimal = 2 1 8 8 0 0 1 1 = 0x21880011

add $s1, $s1, $s3

R type instruction:
Most significant 6 bits corresponds to R type: 000000

Least significant 6 bits corresponds to add : 100000

rs = $s1 = 10001, rt = $s3 = 10011, rd = $s1 = 10001, shamt = 00000

Binary = 000000 10001 10011 10001 00000 100000

Decimal = 0 17 19 17 0 32

HexaDecimal = 0 2 3 3 8 8 2 0 = 0x02338820

sw $s2, 100($t2)

I type instruction
Most significant 6 bits corresponds to sw: 101011

base = $t2 = 01010

rt = $s2 = 10010

100 in 16 bits = 0000 0000 0110 0100

Binary = 101011 01010 10010 0000000001100100

Decimal = 43 10 18 ---100---

HexaDecimal = A D 5 0 0 0 6 4 = 0xAD500064

7.

0x110A17CC

Binary = 000100 01000 01010 0001011111001100

Decimal = 4 8 10 ---6092---

First 6 bits = 000100 = beq

rs = 01000 = $t0

rt = 01010 = $2

offset = 0001011111001100 = 6092 in decimal = 17CC in Hexadecimal

Instruction: beq $t0, $t2, 6092 or beq $t0, $t2, 0x17CC

0x0800AA23

Binary = 00001000000000001010101000100011

First 6 bits = 000010 = J (jump)

Last 26 bits = 00000000001010101000100011 = 43555 in decimal = 0x000AA23 in hexadecimal

Decimal = 2 ----43555---

Instruction: j 43555 or j 0x000AA23

0x8D1400C4

Binary = 100011 01000 10100 0000000011000100

First 6 bits = 100011 = lw (load word)

base = 01000 = $t0

rt = 10100 = $s4

offset = 0000000011000100 = 196 in decimal = 0x00C4

Decimal = 35 8 20 ---196---

Instruction = lw $s4, 196($t0) or lw $s4, 0x00C4($t0)

0x01505020

Binary: 000000 01010 10000 01010 00000 100000

Decimal = 0 10 16 10 0 32

First 6 bits = R type

Least 6 bits = 100000 = ADD

rs = 01010 = $t0

rt = 10000 = $s0

rd = 01010 = $t0

shamt = 00000

Instruction = add $t2, $t2, $s0

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.