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Given a link with a maximum transmission rate of 13.1 Mbps. Only two computers,

ID: 3880245 • Letter: G

Question

Given a link with a maximum transmission rate of 13.1 Mbps. Only two computers, X and Y, wish to transmit starting at time t = 0 seconds. Computer X sends fileX (3 MiB) and computer Y sends fileY (332 KiB), both starting at time t = 0.

Statistical multiplexing is used, with details as follows

Packet Payload Size = 1000 Bytes

Packet Header Size = 24 Bytes (overhead)

Ignore Processing and Queueing delays

Assume partial packets (packets consisting of less than 1000 Bytes of data) are padded so that they are the same size as full packets.

Assume continuous alternating­packet transmission.

Computer X gets the transmission medium first.

At what time (t = ?) would FileX finish transmitting?

Explanation / Answer

Each Packet Size = 1024 bytes (1000 bytes + 24 bytes)

X gets the transmission first.

Number of packets X has to send = 3000000 / 1000 = 3000 packets.

Number of packets Y has to send = 332000 / 1000 = 332 packets.

Time for one packet to transmit :

13100000 bytes in 1 sec

1024 bytes in = (1/13100000) * 1024 = .00007817 secs.

Time taken for X to send = 3000 * .00007817 = .235 secs

Time taken for Y to send = 332 * .00007817 = .026 secs

Time at which File x would finish transmitting = .235 + .026 = .261 secs.

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