NASM 32-bit Assembly Language for program: You are to read in N integers, termin

Question

NASM 32-bit Assembly Language for program:

You are to read in N integers, terminated by entering zeroes two times in a row. (These two zeroes will not be counted.) Write a program which will determine the number of positive, negative and zero numbers in the numbers that have been read in. Negative numbers can always be discerned because their most significant bit will be 1. Numbers that are zero have all bits equal to 0. Positive numbers are those in which the most significant bit is 0, but not all bits are.

Explanation / Answer

%macro scall 4 mov eax,%1 mov ebx,%2 mov ecx,%3 mov edx,%4 int 80h %endmacro section .data arr dd -18888888h,18888888h,22222222h,11111111h n equ 4 pmsg db 10d,13d,"The Count of Positive No: ",10d,13d plen equ $-pmsg nmsg db 10d,13d,"The Count of Negative No: ",10d,13d nlen equ $-nmsg nwline db 10d,13d section .bss pcnt resq 1 ncnt resq 1 char_answer resb 8 section .text global _start _start: mov esi,arr mov edi,n mov ebx,0 mov ecx,0 up: mov eax,[esi] cmp eax,00000000h js negative positive: inc ebx jmp next negative: inc ecx next: add esi,4 dec edi jnz up mov [pcnt],ebx mov [ncnt],ecx scall 4,1,pmsg,plen mov eax,[pcnt] call display scall 4,1,nmsg,nlen mov eax,[ncnt] call display scall 4,1,nwline,1 mov eax,1 mov ebx,0 int 80h ;display procedure for 32bit display: mov esi,char_answer+7 mov ecx,8 cnt: mov edx,0 mov ebx,16h div ebx cmp dl,09h jbe add30 add dl,07h add30: add dl,30h mov [esi],dl dec esi dec ecx jnz cnt scall 4,1,char_answer,8 ret

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