PLEASE GIVE THE FULL DETAILS OF THE STEPS ON EACH QUESTIONS SO I COULD FOLLOW UP

Question

PLEASE GIVE THE FULL DETAILS OF THE STEPS ON EACH QUESTIONS SO I COULD FOLLOW UP YOUR WHOLE EXPLANATIONS.

PLEASE WRITE THE STEPS ON EX) STEP 1, STEP 2, ETC

HANDWRITING IS OKAY AS LONG AS IT IS READABLE.

IF YOU HAVE USED THE EQUATIONS OR CONCEPTS, PLEASE STATE IT CLEARLY WHICH ONE YOU HAVE YOU USED SO I COULD FULLY UNDERSTAND THE DETAILS OF THE STEPS YOU HAVE DONE.

PLEASE DO NOT OMIT THE DETAILS OF STEPS AND CONCEPTS YOU HAVE USED, CLEARLY STATE IT!!

PLEASE INCLUDE THE TABLES OR DRAWINGS IF IT CAN BE VISUALIZED (STACK DIAGRAMS, ARRAY (ARROW), ETC)

Smallest number with sum of digits as N and divisible by 10^N.

Object Oriented concept, Polymorphism , Method overloading, method overriding, Difference between abstraction and encapsulation, Aggregation and Composition.

DeadLock example code.

Explain database normalization?

Explanation / Answer

Object Oriented concept: It simply nothing but every thing sholud be commincated with objects,that means the data should be tranformed in the form of objects and via comminacated with objects only.

polymorphism means having many forms.
polymorphism means that a call to a member function will cause a different function to be executed depending on the type of object that invokes the function.

#include <iostream>
using namespace std;

class Shape {
protected:
int width, height;
  
public:
Shape( int a = 0, int b = 0){
width = a;
height = b;
}
int area() {
cout << "Parent class area :" <<endl;
return 0;
}
};
class Rectangle: public Shape {
public:
Rectangle( int a = 0, int b = 0):Shape(a, b) { }
  
int area () {
cout << "Rectangle class area :" <<endl;
return (width * height);
}
};

class Triangle: public Shape {
public:
Triangle( int a = 0, int b = 0):Shape(a, b) { }
  
int area () {
cout << "Triangle class area :" <<endl;
return (width * height / 2);
}
};

// Main function for the program
int main() {
Shape *shape;
Rectangle rec(10,7);
Triangle tri(10,5);

// store the address of Rectangle
shape = &rec;

// call rectangle area.
shape->area();

// store the address of Triangle
shape = &tri;

// call triangle area.
shape->area();

return 0;
}

Overloading and Overriding:
overloading means functions with same name having different parameters , it does not really depend whether you are using procedural language or object oriented language you can do overloading. well as far as over riding is concerned it means we are explicitly defining a function that exist in base class in derived class . obviously you need object oriented language to perform over riding as it is done between base and derived classes.
for overriding the base class and derived class ha same function name and same paramters but it will took dervied class function to replace the base class method.

Abstraction is a process to abstract or hide the functionality and provide users or other programmers to use it only.

Encapsulation means to encapsulate or put everything into one thing and provide others to use.Here simply we can say the combination of data menber and member fuctions.

Aggregation is a special form of association. It is a relationship between two classes like association, however its a directional association, which means it is strictly a one way association. It represents a HAS-A relationship.
example:It hows the has a realtionip.

Composition is a specialized form of aggregation in which if the parent object is destroyed, the child objects would cease to exist. It is actually a strong type of aggregation and is also referred to as a "death" relationship.

#include <stdio.h>
#include <pthread.h>

void* joinit(void* tid)
{
printf("In %#x, waiting on %#x ", pthread_self(), (*((pthread_t*)tid)));
pthread_join((*((pthread_t*)tid)), NULL);
printf("Leaving %#x ", pthread_self());
return NULL;
}

int main(void)
{
pthread_t thread1 = pthread_self();
pthread_t thread2;
pthread_create(&thread2, NULL, joinit, &thread1);
joinit(&thread2);
return 0;
}

here are simple code while forming a deadlock.
p1 thread is inc with reource r1 and p2 thread is also sync with reourece R1 it will not form beacuse reourece R1 is also sync with P1 then will form the dead lock this is the sutuation will occurs.

Database Normalization:normalization is about the structure of a relational schema,simply we can say to minimise redundant data and to prevent update anomalies.

It contains 5 normalization forms based on them we have minminze the unwnated rows and colums

here we have to find the smallet number to be find

here i the logic to find the smallest number which is divisble by 10 ^ N

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