PYTHON (PLEASE SHOW OUTPUT): PREVIOUS PROBLEM: The h-dependent range equation de
ID: 3882729 • Letter: P
Question
PYTHON (PLEASE SHOW OUTPUT):
PREVIOUS PROBLEM:
The h-dependent range equation derived in part (a) of the previous problem makes t easy to figure out how far something will go for a given launch angle. But what if you want to know what launch angle to use to hit a target at a known range R? It's possible to invert the equation, but it's quite difficult algebraically... Instead, let's use a computer What we have is Rf(), assuming that v and h are constants. The usual way to solve things computationally is to rearrange this like so: F() /(0)-R. Having done that, we can plot F(9), and graphically determine the value of for which F() = 0. Using Python, write a function F(0) that returns the value of f(0)-R, Plot F(0) versus and zoom in on the resulting graph to determine the value of for which F(9-0. You may have to try a few different range values for as a way of zooming in. Report your answers to at least two decimal places. Be sure to save your work; you'll need it next week. Use these values: R = 2.5 m, h = 1.2 m, u = 4.8 m/s. There may be more than one correct answer.Explanation / Answer
function F(theta) which return
def F(theta):
s= f(theta) - R
return s
theta =2.0
R=2.5
Previous problem solution
a ) R=u2 * sin2(theta) / g;
b) when h=0 .the object travels in horizontal direction.
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