Write a program in JAVA to read in a 32-bit pattern and translate to a IEEE-754

Question

Write a program in JAVA to read in a 32-bit pattern and translate to a IEEE-754 floating point number. Do not use library routines. Be sure to look for infinity, -infinity, zero and NaN patterns. ( This is what I NEED, please use the import: import javax.swing.JOptionPane; for the input and outputs, a string to turn the int to binary,then a loop to check and see if there are any special patterns, example: NaN, -infinity, infinity, if there isnt any special patterns check with something else "LIKE" this code below, not exactly just an example

sign=(inputString.CharAt(0)=='0'?1:-1);

String expString=inputString,substring(1,8);

String mainString=inputSting.substring(9)

Explanation / Answer

import javax.swing.JOptionPane;

public class IEEE_754_2 {

public static void main(String[] args) {

String inputString,ieee_754;

inputString = JOptionPane.showInputDialog("Enter the 32bit number");

//In the 32 bit First digit is sign, next 8 are the exponent and finally, the last 23 are the significand.

//Floating point number is calculated by sign * 2^exp * Significand

if(null!=inputString && inputString.length()==32 && inputString.matches("[01]{32}")){

int sign=(inputString.charAt(0)=='0'?1:-1);//0 is postive

String expString=inputString.substring(1,9);

String mainString=inputString.substring(9);

int intExp = Integer.parseInt(expString, 2);

intExp = intExp -127;

double fraction =0.0;

for(int index=0; index <mainString.length();index++){

fraction = fraction + Integer.parseInt(""+mainString.charAt(index))*Math.pow(2,-1*(index+1));

}

ieee_754=""+(fraction+1)*sign*Math.pow(2,intExp);

JOptionPane.showMessageDialog(null,ieee_754);

}

else{

JOptionPane.showMessageDialog(null,"Please Enter Valid Input");

}

}

}

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