38% D 8:10 AM instructure-uploads.s3.amazonaws.com ..ooo AT&T; 17. What is the s
ID: 3883664 • Letter: 3
Question
38% D 8:10 AM instructure-uploads.s3.amazonaws.com ..ooo AT&T; 17. What is the subnet address of host 200.10.5.68 /28? a. 200.10.5.56 b. 200.10.5.32 c. 200.10.5.64 d. 200.10.5.0 18. What is the subnet ID of host 172.16.66.0/21? a. 172.16.36.0 b. 172.16.48.0 c. 172.16.64.0 d. 172.16.0.0 19. You are to configure a server that is on subnet 192.168.19.24 /29. The router has the the first available address. a. 192.168.19.0/24 b. 192.168.19.33 /28 c. 192.168.19.26 /29 d. 192.168.19.31 /29 e. 192.168.19.34 /28 The server gets the second one. Which is it? 20. How many subnets are possible for network 100.0.0.0 sub-netted with a mask of 255.255.240.0? (Not multiple-choice. Write the answer.)Explanation / Answer
17. C. 200.10.5.64
As give A/28 is 255.255.255.240 which means over block size is 16
0, 16, 32, 48, 64, 80 etc.
18. C. 172.16.64.0
A /21 is 255.255.248.0 which means block size of 8 so the broadcast address of the 64 subnet
20. N = 12 bits
number of host per subnet we use formula (2^n)-2 so 4096-2 = 4094 host per subnet.
17. subnet of host 172.16.66.0/21
The ip address in binary format is:
10101100.00010000.01000010.00000000
Here /21 means we have to put all 1’s at all 21 bits of the ip address starting from the left.
By performing BITWISE AND operation between The subnet mask and the original ip gives subnet id.
Ans: 172.16.64.0
18. subnet address of 200.10.5.68/28
11110000 – increment bit is on 16
200.10.5.0 – 200.10.5.15
200.10.5.16 – 200.10..5.31
200.10.5.32 – 200.10.5.47
200.10.5.48 – 200.10.5.63
200.10.5.64 – 200.10.5.79
Therefore answer is: 200.10.5.64
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