Write a program in java which takes as input a string representation of an unsig

Question

Write a program in java which takes as input a string representation of an unsigned hexadecimal number in 32 bits and returns the positive integer that is the base 10 equivalent.

You do not need to worry about negative values for this question

You can use a dictionary, or brute force to convert hex digits to numbers (i.e. write a function with a bunch of if statements or a select statement to deal with digits A-F. or store the values 0-F as keys in a dictionary with the values being the number the digit represents.

For both programs, all non-decimal numbers should be assumed to be 32-bit. When inputting or outputting binary or hex, please make sure the numbers represented are full 32-bit numbers. Do not leave off the leading 0’s or 1’s.

Binary: 00001111110111010101111111011101 (32 digits) Hex: 0FDD5FDD (8 digits long)

Explanation / Answer

JAVA Program:-

import java.math.BigInteger;

import java.util.*;

public class HexaBinary {

public static void main(String[] args) {

// TODO Auto-generated method stub

Scanner scanner=new Scanner(System.in);

System.out.println("Enter a HexaDecimal String ");

String hexa=scanner.next();

//Converting String to demial number.

int num = (Integer.parseInt(hexa, 16));

//Converting 32 digit Binary String.

String bitStr=String.format("%032d", new BigInteger(Integer.toBinaryString(num)));

System.out.println("Eqivelent Binary(32-digit) Value is :- "+bitStr);

//8 digit Hexa value String

String bitHexa=String.format("%0"+ (8 - hexa.length() )+"d%s",0 ,hexa);

System.out.println("Eqivelent HexaDecimal(8-Digit) Value is :- "+bitHexa);

System.out.println("Eqivelent Decimal Value is :- "+num);

}

}

Output:-

Enter a HexaDecimal String
FDD5FDD
Eqivelent Binary(32-digit) Value is :- 00001111110111010101111111011101
Eqivelent HexaDecimal(8-Digit) Value is :- 0FDD5FDD
Eqivelent Decimal Value is :- 266166237

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