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In Java, write a method named as getUncommonDigit with two dimensional array. (n

ID: 3884304 • Letter: I

Question

In Java, write a method named as getUncommonDigit with two dimensional array. (no library and no global data are allowed)

I have written a code below but I got stuck on it. It is okay if help me with entirely new code!

public static int[] getUncommonDigit(int[] ary) {

int[] ucdAry = null;
int ucdCount = 0;
//int[][] dcInfoAry = null;
int[][] dcInfoAry = new int[ary.length][10];
int temp;
  
for (int i = 0; i < ary.length; i++) {
temp = (ary[i] < 0) ? -ary[i] : ary[i];
do {
dcInfoAry[i][temp % 10] = 1;
temp /=10;
} while (temp != 0);
}
//running through a loop to add all array element values
//for each digit (i.e., index).
  
//if the individual sum is the same as 1, the digit is
//uncommon, otherwise, it is NOT!
//Extracting the digits [i.e., the indices after
//confirming its uncommon behavier.
  
return ucdAry;
  
}

Explanation / Answer

public class SubarraySum {

int subArraySum(int arr[], int n, int sum)

{

int curr_sum = arr[0], start = 0, i;

// Pick a starting point

for (i = 1; i <= n; i++)

{

// If curr_sum exceeds the sum, then remove the starting elements

while (curr_sum > sum && start < i-1)

{

curr_sum = curr_sum - arr[start];

start++;

}

// If curr_sum becomes equal to sum, then return true

if (curr_sum == sum)

{

int p = i-1;

System.out.println("Sum found between indexes " + start

+ " and " + p);

return 1;

}

// Add this element to curr_sum

if (i < n)

curr_sum = curr_sum + arr[i];

}

System.out.println("No subarray found");

return 0;

}

public static void main(String[] args)

{

SubarraySum arraysum = new SubarraySum();

int arr[] = {15, 0, -1, 1, 1, 5, 0, 23};

int n = arr.length;

int sum = 1;

arraysum.subArraySum(arr, n, sum);

}

}

output - Sum found between indexes 1 and 4

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