C PROGRAM ONLY! 1. Set hasDigit to true if the 3-character passCode contains a d

Question

C PROGRAM ONLY!

1. Set hasDigit to true if the 3-character passCode contains a digit.

#include <stdio.h>
#include <string.h>
#include <stdbool.h>
#include <ctype.h>

int main(void) {
bool hasDigit = false;
char passCode[50] = "";
int valid = 0;

strcpy(passCode, "abc");

/* Your solution goes here */

if (hasDigit) {
printf("Has a digit. ");
}
else {
printf("Has no digit. ");
}

return 0;
}

2. Replace any space ' ' by '_' in 2-character string passCode. Sample output for the given program:

#include <stdio.h>
#include <string.h>
#include <ctype.h>

int main(void) {
char passCode[3] = "";

strcpy(passCode, "1 ");

/* Your solution goes here */

printf("%s ", passCode);
return 0;
}

3. Write an expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to targetValue. Otherwise, print "Not equal".

#include <stdio.h>
#include <math.h>

int main(void) {
double targetValue = 0.3333;
double sensorReading = 0.0;

sensorReading = 1.0/3.0;

if (/* Your solution goes here */) {
printf("Equal ");
}
else {
printf("Not equal ");
}

return 0;
}

Explanation / Answer

//Please see the answers below please do thumbs up if you like the solutions

1. Set hasDigit to true if the 3-character passCode contains a digit

#include <stdio.h>
#include <string.h>
#include <ctype.h>
#include<iostream>
using namespace std;

int main(void) {
   bool hasDigit = false;
   char passCode[50] = "";
   int valid = 0;

   strcpy(passCode, "abc");

   /* Your solution goes here */
   int i=0;
   while(passCode[i])
   {
       if(passCode[i]>='0' && passCode[i]<'9')
       {
           hasDigit=true;
       }
       i++;
   }

   if (hasDigit) {
      printf("Has a digit. ");
   }
   else {
      printf("Has no digit. ");
   }

   return 0;
}

OUTPUT:

Has no digit.

2. Replace any space ' ' by '_' in 2-character string passCode. Sample output for the given

#include <stdio.h>
#include <string.h>
#include <ctype.h>

int main(void) {
   char passCode[3] = "";

   strcpy(passCode, "1 ");

   /* Your solution goes here */
   int i=0;
   while(passCode[i])
   {
       if(passCode[i]==' ')
       {
       passCode[i]='_';
       }
       i++;
   }

   printf("%s ", passCode);
   return 0;
}

OUTPUT:

1_

3. Write an expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to targetValue. Otherwise, print "Not equal".

#include <stdio.h>
#include <math.h>

int main(void) {
   double targetValue = 0.3333;
   double sensorReading = 0.0;
   double epsilon = 0.000000001;
   sensorReading = 1.0/3.0;

   if (abs(targetValue - sensorReading) < epsilon) {
      printf("Equal ");
   }
   else {
      printf("Not equal ");
   }

   return 0;
}

OUTPUT:

Not equal

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