C programming please type it don\'t write on a paper thank you an advance. progr

Question

C programming

please type it don't write on a paper

thank you an advance.

program Structure:

// Import LCD Library

#

include

<LiquidCrystal.h>

// Defines for LCD

LiquidCrystal LcdDriver(11

, 9, 5, 6, 7, 8

)

;

int count;

SetUp:

Start LCD

clear the display

zero count

Loop:

Every 500 milliseconds

Increment count

Clear Display

Display count

Explanation / Answer

#include LiquidCrystal LcdDriver(11, 9, 5, 6, 7, 8); int minutes = 27; //These global integers keep the value of the clock int sec = 10; int hr = 10; const long interval = 1000; //This interval is equal to 1 second and will be added to seconds unsigned long oldMillis = 0; int count; void setup() { // put your setup code here, to run once: LcdDriver.begin(16, 2); LcdDriver.clear(); LcdDriver.setCursor(0, 0); } void loop() { //LcdDriver.setCursor(0,1); unsigned long currentMillis = millis(); //This sets up the timer so that it can add one second to the integer if(currentMillis - oldMillis >= interval) { oldMillis = currentMillis; sec++; LcdDriver.clear(); LcdDriver.setCursor(0, 0); LcdDriver.print(" Current Time"); LcdDriver.setCursor(4, 1); if(hr < 10) { //Prints an extra 0 if hr < 10 LcdDriver.print(0); LcdDriver.print(hr); LcdDriver.print(":"); } else { //Print no zero if hours > 10 LcdDriver.print(hr); LcdDriver.print(":"); } if(minutes < 10) { //Prints an extra 0 if minutes < 10 LcdDriver.print(0); LcdDriver.print(minutes); LcdDriver.print(":"); } else { //Print no zero if minutes > 10 LcdDriver.print(minutes); LcdDriver.print(":"); } if(sec < 10) { //Prints an extra 0 if seconds < 10 LcdDriver.print(0); LcdDriver.print(sec); } else { //Print no zero if seconds > 10 LcdDriver.print(sec); } //Adds to minutes whenever seconds is == to 59 if(sec == 59) { minutes++; sec = -1; } //Adds to hours whenever minutes is == to 59 if(minutes == 60) { hr++; minutes = 0; } //Resets the clock whenever hours is == to 23 if(hr == 24) { hr = 0; } } }

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