communication system Q&A HELP !!! Please help me show the all answers and show h
ID: 3889622 • Letter: C
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communication system Q&A HELP !!!
Please help me show the all answers and show how to get the answers for the all steps, thank you so much !!!
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Version 1 Total 40 marks Name: Class: Q A data modem transfers information at 192 kbps using 32-level baseband signal overa 10 marks] distortion-free transmission link. (a) How many bits are encoded into each symbol? (b) Determine the symbol rate. (c) What is the minimum bandwidth for the transmission link? (d) What is the bandwidth cfficiency of the link? Q2 An information source produces sequences of independent symbols having the following probabilities. Symbols robabiities 0.36 codes 0.12 0.07 0.07 0.07 0.07 100 101 1100 1101 1110 (a) Evaluale the entropy of the code (b) Lvaluate the averagc code length. (c) Lvaluate the coding cfficiency (d) Ilow many bits are required for a symbol without coding? [4 marks] 13 marksl 12 marksl |1 markl Q3 (a) A block code is designed with a minimum Hamming distance ol 7 () How many error bits can be corrected? (ii) Ilow many crror bits can be detected? (iii) What is mcant by Ilamming distancc? [1 mark] |1 markl 12 marksl Assuming that a (31, 26) block code is used for crror control, determine: (i) he number of bits in the output block (n), (ii) the number of bits in the input block (k), (iii) the code rate of the block code, (iv) the redundancy rate of the block code (b) [1 mark] [1 mark] 1 mark] I1 mark] (c) What is the signal to quantization noise ratio for an 8-bit converter expressed in dB? [2 marks] An audio signal with a frequency range of 100 to 15 klHz is transmitted using a PCM 10 marksl with 256 quantization levels. (a) Calculate the number of bits per each sample (b) Determine the minimum sampling frequency (c) Calculate the bit rate (d) Find the guard band for a 40 kHz sampling frequency Q4Explanation / Answer
a)Since it is a 32 level baseband, we know that 2^n = 32, where n is the number of bits.
=>n=5
Number of bits encoded in each symbol is 5
b)We know symbol rate is equal to (bit rate)/no of bits)
=>symbol rate=192*1000/5 bps
Therefore, symbol rate is 38400 baud.
c)Symbol rate, or Baud rate is equal to the minimum bandwidth.
Minimum bandwidth = 38400Hz
d)Bandwidh efficiency=(Bit rate) / (Min Bandwidth)
=>Bandwidth efficiency=192*1000/38400=5bps/Hz
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