Help me A 5.00-kg particle moves from the origin to position C, having coordinat
ID: 3892264 • Letter: H
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A 5.00-kg particle moves from the origin to position C, having coordinates x = 5.50 m and y = 5.50 m as shown in the figure. One force on the particle is the gravitational force acting in the negative y direction. Using the equation (W = F Delta r cos theta = ), calculate the work done by the gravitational force in going from O to C along the following paths. the purple path (OAC) The gravitational force acts downwards. The displacement in going from A to C is upwards. Does the gravitational force do positive or negative work during this displacement?] the red path (OBC) How does the work done in moving from O to B compare to the work done in moving from A to C?] the blue path (OC) Your results should all be identical. Why? The potential energy of a system of two particles separated by a distance r is given by the equation below, where A is a positive constant. Find the radial force F that each particle exerts on the other. (Use any variable or symbol stated above as necessary.) and is pointing from the other particleExplanation / Answer
Work done along path OAC = M*g*H ,=5*9.82*5.5=270 joules
Where M= mass
g=9.82m/s^2
H= verticle height ,(in y direction)
Work done along path OBC =5*9.82*5.5=270 Joules
Work done along path OC=5*9.82*5.5=270 joules
Work done in all paths are same because gravitational is a conservative field and work done depends on difference between intial and final postion verticle distance .It is indeoendent of the path taken by body
Force = differencial of potential energy = -A/ (r12)^2
and it acts towards the other particle , gravitational force in attractional in nature
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